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igor_vitrenko [27]
3 years ago
11

How many liters of 10% alcohol solution and 5% alcohol solution must be mixed to obtain 40 liters of 8%

Mathematics
1 answer:
Likurg_2 [28]3 years ago
4 0

Answer:

x+y=40liters

10%x+5%y=8%×40

(2x+y)/20=8%×40

(2x+y)=64

x=24

y=16

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