How many liters of 10% alcohol solution and 5% alcohol solution must be mixed to obtain 40 liters of 8%
1 answer:
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Answer:
We'll use the Law of Sines:
Sine (C) / c = Sine (B) / b
Sine (86) / 40 = Sine (52) / b
0.99756 / 40 = 0.78801 / b
0.024939 = .78801 / b
b = .78801 / .024939
side b = 31.5974978949 feet
Sine (42) / a = Sine (86) / 40
(0.66913 / a) = 0.024939
a = .66913 / .024939
side a = 26.8306668271 feet
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I forgot to include the graphic.
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