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igor_vitrenko [27]
3 years ago
11

How many liters of 10% alcohol solution and 5% alcohol solution must be mixed to obtain 40 liters of 8%

Mathematics
1 answer:
Likurg_2 [28]3 years ago
4 0

Answer:

x+y=40liters

10%x+5%y=8%×40

(2x+y)/20=8%×40

(2x+y)=64

x=24

y=16

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Step-by-step explanation:

papa math will help you

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Step 1: Multiply both sides by 9.

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https://www.mathpapa.com/algebra-calculator.html?q=(x%E2%88%923)%5Cdiv9%3D11

x−3

9

=11

Step 1: Multiply both sides by 9.

x−3

9

=11

(

x−3

9

)*(9)=(11)*(9)

x−3=99

Step 2: Add 3 to both sides.

x−3+3=99+3

x=102

Answer:

x=102

Close Ad

Back to Algebra Calculator »

Share this page

Share URL:

https://www.mathpapa.com/algebra-calculator.html?q=(x%E2%88%923)%5Cdiv9%3D11

x−3

9

=11

Step 1: Multiply both sides by 9.

x−3

9

=11

(

x−3

9

)*(9)=(11)*(9)

x−3=99

Step 2: Add 3 to both sides.

x−3+3=99+3

x=102

Answer:

x=102

Close Ad

Back to Algebra Calculator »

Share this page

Share URL:

https://www.mathpapa.com/algebra-calculator.html?q=(x%E2%88%923)%5Cdiv9%3D11

6 0
3 years ago
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Sholpan [36]
Answer: A I think
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3 years ago
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