Answer:
8
Step-by-step explanation:
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Answer:
F(h,k)=(6,4)
(p)horizontal line =6 units
we. have
y=1(x-h)²/4p+k
substituting value we get
y=(x-6)/(4×6)+4
24y=x-6+96
x-24y+90=0 is a required equation.
I cannot help. please attach a graph.
Answer:
The point N lies inside the circle
Step-by-step explanation:
A circle is centered at the point T(-6,3) and has a radius of r=1.
To determine if the point N(3,-3) is inside or outside the circle, the distance between N and the point T must be lower than 11.
To calculate the distance between points T and N you use:
![d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D)
where x1 and y1 are the coordinates of T, and x2 and y2 the coordinates of N.
![d=\sqrt{(3-(-6))^2+(-3-3)^2}=\sqrt{9^2+6^2}=10.81](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%283-%28-6%29%29%5E2%2B%28-3-3%29%5E2%7D%3D%5Csqrt%7B9%5E2%2B6%5E2%7D%3D10.81)
d < 11
The distance d is lower than the radius of the circle. Hence, the point N lies inside the circle