I REALLY NEED HELP ON THIS!!! HELP ASAP PLS!!! EXTRA POINTS TO THE FIRST PERSON WHO ANSWERS!!

A website developer wished to analyze the clicks per day on their newly updated website. Let the mean number of clicks per day b

beks73 [17]

Answer:

Null Hypothesis, $H_0$ : $\mu$ = 200 clicks a day

Alternate Hypothesis, $H_A$ : $\mu\neq$ 200 clicks a day

Step-by-step explanation:

We are given that a website developer wished to analyze the clicks per day on their newly updated website.

The website developer wants to know if the number of clicks per day is different than 200 clicks a day, on average.

Let $\mu$ = <u><em>mean number of clicks per day.</em></u>

So, Null Hypothesis, $H_0$ : $\mu$ = 200 clicks a day

Alternate Hypothesis, $H_A$ : $\mu\neq$ 200 clicks a day

Here, the null hypothesis states that the mean number of clicks per day is 200 clicks a day.

On the other hand, the alternate hypothesis states that the mean number of clicks per day is different than 200 clicks a day.

Hence, this is the correct null and alternative hypotheses.

4 0

3 years ago

Read 2 more answers

Beth is writing out the steps using the "Shortest Route Algorithm". She just finished writing out all

JulijaS [17]

Answer:

ACBD; 7

Step-by-step Explanation:

The Route Algorigtm finds the short route that is efficient, in order to find the solution following pathways.

From the pictures from the complete question,

STEP #1, there exist, three routes, which are:

AB

AC,

and AD.

*AB is not viable because of the negative distance, so it can be removed .

* the AC distance is 3,and AD distance is 8. Therefore, AC can be selected and circled.is because of AC efficiency is high compare to AD.

*from selected AC, the possible routes are ACB; 3 and ACE; 6. which are route shown in #2

* ACB is circled, because it's more shorter than ACE

*The possible routes are ACBE; 8 and ACBD; 7. which are route shown in #3 . Therefore, route ACBD is circled because it's more shorter.

From the analysis of the algorithm, the route ACBD route is the shortest and the most efficient

5 0

3 years ago

Please help! geometry problem 3!

Vilka [71]

Comment
|First of all, the triangles are equal by ASA the way the diagram has been marked.

B and E are both right angles.
Side BC = Side DE
<BCA =< EDA

So triangle BCA = triangle EDA

Now to the letters.
x = y - 1 Add 1 to both sides.
x + 1 = y (1)
3x - 2 = 2y + 1 Subtract 1 from both sides.
3x -2 - 1 = 2y
3x - 3 = 2y Divide by 2
3x/2 - 3/2 = 2y/2
1.5x - 1.5 = y (2)

Step One
Since (1) and (2) both have y isolated on their respective right sides, they can be equated.

1.5x - 1.5 = x + 1 Take an x from both sides.
0.5x - 1.5 = x - x + 1
0.5x - 1.5 = 1 Add 1.5 to both sides.
0.5x = 1 + 1.5
0.5x = 2.5 Divide 0.5 on both sides.
0.5x/0.5 = 2.5/0.5

x = 5

Now we need a y value.
x = y - 1
5 = y - 1 Add 1 to both sides.
5 + 1 = y - 1 + 1
6 = y

So the 2 sides and the 2 angles are equal when
x = 5
y = 6

C Answer <<<<<<

4 0

2 years ago

How to multiply a whole number and a mixed fraction?

Ugo [173]

Convert the mixed number into a decimal and multiply on a calculator (or by hand).

4 0

3 years ago

Diego’s dog weighs more than 10 kilograms and less than 15 kilograms. Select the set of inequalities that must be true if w is t

hichkok12 [17]

Answer:

Step-by-step explanation:

Correct

w > 10

Incorrect

w < 10

Incorrect

w > 11

Incorrect

w < 11

Correct

w < 15

w < 15Correct

w > 10

Incorrect

w < 10

Incorrect

w > 11

Incorrect

w < 11

Correct

w < 15

w < 15Correct

w > 10

Incorrect

w < 10

Incorrect

w > 11

Incorrect

w < 11

Correct

w < 15

w < 15Correct

w > 10

Incorrect

w < 10

Incorrect

w > 11

Incorrect

w < 11

Correct

w < 15

w < 15Correct

w > 10

Incorrect

w < 10

Incorrect

w > 11

Incorrect

w < 11

Correct

w < 15

w < 15Correct

w > 10

Incorrect

w < 10

Incorrect

w > 11

7 0

2 years ago