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3 years ago

Is 1 equal to or greater then -1?

Mathematics

2 answers:

Gnesinka [82]3 years ago

7 0

Answer: greater than one

Step-by-step explanation:

1 is greater than -1 because when you subtract something you are removing something which in this case you wouldn't be removing anything except your number.

Lina20 [59]3 years ago

4 0

Answer:

1 is greater than -1

Step-by-step explanation:

And positive number is greater the a negative

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Someone please help me with this algebra

labwork [276]

$QUADRATIC \: \: \: RESOLUTIONS \\ \\ \\ \\Function \: to \: model \: the \: height \: of \: the \\ Grasshopper \: above \: the \: ground \: is \: \\ given \: by \: \: - \\ \\ h(t) \: \: = \: \: - {t}^{2} \: + \: \frac{4}{3} t \: + \: \frac{1}{4} \\ \\ \\ When \: the \: grasshopper \: will \: be \: at \: \\ the \: ground \: , \: \: \\ \\ h(t) \: = \: 0 \\ \\ - {t}^{2} \: + \: \frac{4}{3} t \: + \: \frac{1}{4} \: = \: 0 \\ \\ - 12{t}^{2} \: + \: 16 t \: + 3 \: = \: 0 \\ \\ \: \: \: 12 {t}^{2} \: - \: 16t \: - \: 3 \: = \: 0 \\ \\ \: \: \: 12 {t}^{2} \: + \: 2t \: - \: 18t \: - 3 \: = \: 0 \\ \\ \: \: 2t \: (6t + 1) \: - 3 \: (6t + 1) \: = \: 0 \\ \\ \: (2t - 3) \: (6t + 1) \: \: = \: \: 0 \\ \\ Neglecting \: the \: negative \: value \: \\ as \: time \: cannot \: be \: negative \: \: ,\\ \\ We \: get \: \: - \: \\ \\ t \: \: = \: \: \frac{3}{2} \\ \\ \\ Hence \: \: , \: \: After \: \: || \: \: 1.5 \: seconds \: \: || \: , \: the \: \\ Grasshopper \: will \: land \: on \: the \: ground \: .$

3 0

3 years ago

9. The length of each side of a square with area 2500 square inches is increased by 10 inches. What

shusha [124]

Answer: 3600

Step-by-step explanation:

Area of a square = side^2

Area = √2500 = 50

If side is increased by 10, length if side becomes 60 inches

Area = 60^2

Area = 3600 sq. in.

7 0

4 years ago

What is the length of the third side of the window frame below?

Phantasy [73]

Answer: second option

Step-by-step explanation:

You know that it is a right triangular window frame.

Then, you can use the Pythagoren Theorem to find the lenght of the third side:

$a^2=b^2+c^2$

Where "a" is the hypotenuse (or the longest side), and "b" and "c" are the legs .

Then, you can solve for one of the legs:

$b^2=a^2-c^2\\b=\sqrt{a^2-c^2}$

Since you know the lenght of the hypotenuse and the lenght of one leg, you can substitute values.

Therefore, you get:

$b=\sqrt{(87in)2^-(63in)^2}\\b= 60in$

4 0

3 years ago

An employee will spend 2/3 of his time each day answering phone calls each day he will work 6.5 hours how many hours will the em

leva [86]

$\frac{2}{3} (time)= \frac{2}{3}(6.5)= \frac{13}{3} =4 \frac{1}{3}$
That is the number of hours he will spend answering phone calls.

6 0

3 years ago

Evaluate the limit, if it exists. (if an answer does not exist, enter dne.) lim h → 0 (−6 + h)2 − 36 h

Lyrx [107]

The limit can be found by simplifying the expression.
$\lim\limits_{h\rightarrow 0}\left(\dfrac{(-6+h)^{2}-36}{h}\right)=\lim\limits_{h\rightarrow 0}\left(\dfrac{-12h+h^{2}}{h}\right)\\\\=\lim\limits_{h\rightarrow 0}(-12+h)\\\\=-12$

The limit is -12.

3 0

3 years ago

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