Answer:
1200-928 = 272 for the rest of the month Clarissa has to spend.
Step-by-step explanation:
So we don't want her to go over her budget so we wouldn't choose a greater than option for her so eliminate the first option and the last option. Now we just have the middle two. We want to keep it under 1200 but theres nothing wrong with spending that exact amount each month so I would pick x less than or equal to 272, since we can still equal the total of less than the total and not go over. Option 2 or B.
Answer:
B
Step-by-step explanation:
its a graph and I agree math is dumb
Answer:
The number generator is fair. It picked the approximate percentage of red lollipops most of the time.
Step-by-step explanation:
The other answer choices represent various misinterpretations of the nature of the experiment or the meaning of the numbers generated.
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A number generator can be quite fair, but give wildly varying percentages of red lollipops. Attached are the results of a series of nine (9) simulations of the type described in the problem statement. You can see that the symmetrical result shown in the problem statement is quite unusual. A number generator that gives results that are too ideal may not be sufficiently random.
Answer:
Victor gives 28 tools to IIya.
Step-by-step explanation:
Consider the provided information
The ratio of the number of Victor’s tools to the number of Ilya’s tools is 5:2
Let V represents the Victor and I represent llya
Therefore,
It is given that Victor has 42 more tools than Ilya.
Solve the above equation.
Thus, IIya has 28 tools.
Victor has 42 more tools than Ilya. Therefore 42 + 28 = 70.
Victor has 70 tools.
We want to find the number of tools victor needs to give to IIya so that the ratio of the number of Victor's tools to the number of Ilya’s tools will be 3:4
Let Victor gives x tools to IIya. Thus,
Hence, Victor gives 28 tools to IIya.
Let's add up the given scores to get: 97+38+88+75+83 = 381. Then we divide by 5 since there are five scores here. The mean we get is 381/5 = 76.2
So that explains the "76.2" mentioned.
Now we'll replace the "38" with "58" and repeat the same steps as above.
Add: 97+58+88+75+83 = 401
Divide by five: 401/5 = 80.2
The mean is now 80.2; it has increased compared to the previous mean. We can see that if we move any outliers closer to the main cluster, then the mean will be centered more around the main cluster. In the other direction, if we move the outlier further away from the cluster, then the outlier pulls on the mean. Think of a magnetic or gravitational pull.
The smaller outlier 38 made the mean of 76.2 to be smaller than it should be if we focused on the other values only. In short, if your data set has outliers, then the mean may likely not reflect the true center average value of the group. At that point, the median may be the next best thing or you could use a trimmed mean.
