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3 years ago

Prove that there exists a pair of consecutive integers such that one of these integers is a perfect square

Mathematics

1 answer:

dybincka [34]3 years ago

7 0

2^3 = 8

3^2 = 9

<span>Hense proved </span>

2 and 3 are consecutive

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9/14 divided by 15/2 as a simplest form

Sholpan [36]

Answer:

The answer to this equation would be 3/35 in simplest form.

Step-by-step explanation:

To divide by a fraction, multiply by its reciprocal.

9 /14 ⋅ 2 /15

You then cross simplify 9 & 15 (can be divided by 3 to get 9=3 and 15=5)

This will then leave you with 3/14 & 2/5

Next, you cross simplify 14 & 2, (both can be divided by 2 to get 14=7 and 2=1)

This will then leave you with 3/7 & 1/5

Then multiply $\frac{3 *1}{ 7*5}$

This will then leave you with your answer of 3/35.

I hope this helps! :)

4 0

2 years ago

Read 2 more answers

A particle moves along a straight line with equation of motion s = f(t), where s is measured in meters and t in seconds. Find th

kirza4 [7]

Answer:

Step-by-step explanation:Find the slope of the line that passes through the points shown in the table.

The slope of the line that passes through the points in the table is

6 0

3 years ago

PLEASE HELP ILL MARK BRAINLIEST

viktelen [127]

Answer:

You would want to do the square root of 361 which is 19

Hope This Helps!

ps. no, I'm not stalking u I just clicked on the next question from your last one.

5 0

2 years ago

Read 2 more answers

Problem 2.9 a runner completes the 200-meter dash with a time of 20.19 seconds. part a what was the runner's average speed in me

Elina [12.6K]

Answer:

Average speed = 9.91 m/s

Explanation :

Total distance covered by a runner = 200 m

Time taken to complete this distance = 20.19 sec

We need to find the average of runner speed in meter/sec

We use the speed, distance, time formula

$speed = \frac{distance}{time}$

speed = $\frac{200}{20.19}$

Average speed = 9.91 m/s

that's the final answer.

I hope it will help you.

8 0

3 years ago

According to the US Census, Virginia had about 7.1 million residents in 2000. Of those, 24.6% were under age 18. To the nearest

Mazyrski [523]

7.1 Million × 0.246 = 1.7466 = 1.7 Million

4 0

3 years ago