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Arlecino [84]
3 years ago
10

Help with bonus question please

Mathematics
1 answer:
Sedbober [7]3 years ago
6 0

Bonus #1) June 30 is equivalent to the 91st day of April or the 61st day of May.

Hilda's deposit of 4520 earned interest for 91-1 = 90 days.

Hilda's deposit of 580 earned interest for 61-10 = 51 days.

Hilda's deposit of 590 earned interest for 61-23 = 38 days.

Balance = $4520·(1 +.035/365)⁹⁰ + 580·(1 +.035/365)⁵¹ + 590·(1 +.035/365)³⁸

... = $4559.175 +582.843 +592.154

... ≈ $5734.17

Deposits total 4520 +580 +590 = 5690, so interest earned is

... $5734.17 -5690.00 = $44.17

Bonus #2)  This problem can be worked the same way, except that withdrawals are subtracted from the final balance.

Owner's deposit of $12,300 earned interest for 91 days.

Owner's withdrawal of $3600 reduced the balance for 53 days.

Owner's withdrawal of $1200 reduced the balance for 10 days.

Balance = $12300·(1 +.035/365)⁹¹ -3600·(1 +.035/365)⁵³ -1200·(1 +.035/365)¹⁰

... = $12,407.795 -3618.342 -1201.151

... ≈ $7588.30

Interest earned = $7588.30 - (12300 -3600 -1200) = $88.30

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