All categories

3 years ago

Help with bonus question please

Mathematics

1 answer:

Sedbober [7]3 years ago

6 0

Bonus #1) June 30 is equivalent to the 91st day of April or the 61st day of May.

Hilda's deposit of 4520 earned interest for 91-1 = 90 days.

Hilda's deposit of 580 earned interest for 61-10 = 51 days.

Hilda's deposit of 590 earned interest for 61-23 = 38 days.

Balance = $4520·(1 +.035/365)⁹⁰ + 580·(1 +.035/365)⁵¹ + 590·(1 +.035/365)³⁸

... = $4559.175 +582.843 +592.154

... ≈ $5734.17

Deposits total 4520 +580 +590 = 5690, so interest earned is

... $5734.17 -5690.00 = $44.17

Bonus #2) This problem can be worked the same way, except that withdrawals are subtracted from the final balance.

Owner's deposit of $12,300 earned interest for 91 days.

Owner's withdrawal of $3600 reduced the balance for 53 days.

Owner's withdrawal of $1200 reduced the balance for 10 days.

Balance = $12300·(1 +.035/365)⁹¹ -3600·(1 +.035/365)⁵³ -1200·(1 +.035/365)¹⁰

... = $12,407.795 -3618.342 -1201.151

... ≈ $7588.30

Interest earned = $7588.30 - (12300 -3600 -1200) = $88.30

You might be interested in

The solution shown for the equation is incorrect. What is the correct solution? What is the error?

Degger [83]

-9(3-r)=45
-27+9t=45
9r=45+27
R=72/9
R=8
The answer is 8 not -8

5 0

3 years ago

Raffle tickets were sold for a school fundraiser to parents, teachers, and students. 563 tickets were sold to teachers. 888 more

Llana [10]

Given :

Raffle tickets were sold for a school fundraiser to parents, teachers, and students. 563 tickets were sold to teachers. 888 more tickets were sold to students than to teachers. 904 tickets were sold to parents.

To Find :

How many tickets were sold to students.

Solution :

Ticket sold to teachers, T = 563 .

Ticket sold to parents, P = 904 .

Let, ticket sold to students are S.

Now, it is given that :

S = T + 904

S = 563 + 904

S = 1467 students

Therefore, tickets sold to students are 1467 .

Hence, this is the required solution.

6 0

3 years ago

Gretchen has a set of blocks of heights 1, 2, and 4-centimeters. Imagine stacking the blocks one on top of the other to make a t

notsponge [240]

Answer:

$t_{n}$ = $t_{n-1}$ + $t_{n-2}$ + $t_{n-4}$

Step-by-step explanation:

$t_{n}$ =multiple ways to climb a tower

When n = 1,

tower= 1 cm

$t_{1}$ = 1

When n = 2,

tower =2 cm

$t_{2}$ = 2

When n = 3,

tower = 3 cm

it can be build if we use three 1 cm blocks

$t_{3}$ = 3

When n = 4,

tower= 4 cm

it can be build if we use four 1 cm blocks

$t_{4}$ = 6

When n > 5

tower height > 4 cm

so we can use 1 cm, 2 cm and 4 cm blocks

so in that case if our last move is 1 cm block then $t_{n-1}$ will be

n —1 cm

if our last move is 2 cm block then $t_{n-2}$ will be

n —2 cm

if our last move is 4 cm block then $t_{n-4}$ will be

n —4 cm

$t_{n}$ = $t_{n-1}$ + $t_{n-2}$ + $t_{n-4}$

4 0

3 years ago

Read 2 more answers

Select all of the points that are solutions to the system of linear inequalities that is listed below 10x + 4y < 12 8x -3y &g

liberstina [14]

Answer:

(3, -8) and (2, -10)

Step-by-step explanation:

Given

$10x + 4y < 12$

$8x - 3y > 20$

Required

Select the true coordinate points in (3, -8) (2, 5) (-5, 1) (10, 3) (2, -10)

(3, -8)

x = 3 and y = -8

$10x + 4y < 12$

$10 * 3 + 4 * -8 < 12$

$30 - 32 < 12$

$-2 < 12$ --- True

$8x - 3y > 20$

$8 * 3 - 3 * -8> 20$

$24 +24> 20$

$48> 20$ --- True

(2, 5)

x = 2 and y = 5

$10x + 4y < 12$

$10 * 2 + 4 * 5 < 12$

$20 + 20 < 12$

$40 < 12$ --- False (No need to check the other inequality)

(-5, 1)

x = -5 and y = 1

$10x + 4y < 12$

$10 * -5 + 4 * 1 < 12$

$-46 < 12$ --- True

$8x - 3y > 20$

$8 * -5 - 3 * 1 > 20$

$-43 > 20$ --- False

(10, 3)

x = 10 and y = 3

$10x + 4y < 12$

$10 * 10 + 4 * 3 < 12$

$112 < 12$ --- False (No need to check the other inequality)

(2, -10)

x = 2 and y = -10

$10x + 4y < 12$

$10 * 2 + 4 * -10 < 12$

$-20 < 12$ --- True

$8x - 3y > 20$

$8 * 2 - 3 * -10 > 20$

$46 > 20$ --- True

Hence, the solution to the inequalities are:

(3, -8) and (2, -10)

4 0

2 years ago

91 more than the square root of a number

Genrish500 [490]

Answer:

Step-by-step explanation:

y = x 2 + 91

Explanation:

Let the number be x

, then Square of the number is x ^2

91 more than the square of a number" will be x^ 2 + 91

So, we can write it as an algebraic expression with two variables as :

y = x ^2 + 91

3 0

3 years ago