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RoseWind [281]
3 years ago
5

Keith ate 2/6 of candy bar. If there were 6 pieces total, what fraction of the candy bar is left?

Mathematics
2 answers:
IgorC [24]3 years ago
5 0
If there were 6 pieces and Keith ate 2 of the pieces, then there would be 4 pieces left.
\frac{4}{6}
and when you reduce it it would be 
\frac{2}{3}
kkurt [141]3 years ago
5 0
To make the answer simpler the answer is 4/6
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| 3 x - 2 | = 4x + 4
Ugo [173]

Answer: -2/7

|3x - 2| - 4x = 4

1) (3х - 2) - 4х = 4, if 3x - 2 >= 0

2) -(3x - 2) - 4x = 4, if 3x - 2 < 0

1)

3х - 4х = 4 + 2

-x = 6

x = -6

3х - 2 >= 0

3х >= 2

x >= 2/3 - wrong

2)

-3х + 2 - 4х = 4

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x = -2/7

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Answer:

\displaystyle A _{ \text{trapezoid}} =  70 {m}^{2}

Step-by-step explanation:

we are given a trapezoid

we want to figure out the area

remember that,

\displaystyle A _{ \text{trapezoid}} =  \frac{a + b}{2} h

where a and b represent the parallel lines and h represents the height

we get from the pic that a and b are 5 and 15 respectively and h is 7

so substitute:

\displaystyle A _{ \text{trapezoid}} =  \frac{5 + 15}{2} \times  7

simplify addition:

\displaystyle A _{ \text{trapezoid}} =  \frac{20}{2} \times  7

simplify division:

\displaystyle A _{ \text{trapezoid}} =  10\times  7

simplify multiplication:

\displaystyle A _{ \text{trapezoid}} =  70

since we multiply two same units we of course have to use square unit

hence,

\displaystyle A _{ \text{trapezoid}} =  70 {m}^{2}

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