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Ainat [17]
4 years ago
8

Three friends all have same ages that are consecutive integers. The sum of their ages is 57. What is the age of the oldest frien

d?
A) 19 yr old
B) 18 yrs old
C) 21 yrs old
D) 20 yrs old
Mathematics
1 answer:
quester [9]4 years ago
7 0

Answer:

20 yrs old

Step-by-step explanation:

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\mathrm{Convert\:mixed\:numbers\:to\:improper\:fractions}:\quad 2\frac{1}{2}=\frac{5}{2}\\=\frac{5}{2}\div \:3\frac{2}{3}\\\mathrm{Convert\:mixed\:numbers\:to\:improper\:fractions}:\quad 3\frac{2}{3}=\frac{11}{3}\\=\frac{5}{2}\div \frac{11}{3}\\\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{b}\div \frac{c}{d}=\frac{a}{b}\times \frac{d}{c}\\=\frac{5}{2}\times \frac{3}{11}\\\mathrm{Multiply\:fractions}:\quad \frac{a}{b}\times \frac{c}{d}=\frac{a\:\times \:c}{b\:\times \:d}\\

\mathrm{Multiply\:fractions}:\quad \frac{a}{b}\times \frac{c}{d}=\frac{a\:\times \:c}{b\:\times \:d}\\=\frac{5\times \:3}{2\times \:11}\\\mathrm{Multiply\:the\:numbers:}\:5\times \:3=15\\=\frac{15}{2\times \:11}\\\mathrm{Multiply\:the\:numbers:}\:2\times \:11=22\\=\frac{15}{22}

5 0
3 years ago
Solve using substitution x+y+2z=-7 / -5z=25 / 3x-3y-6z=3
inn [45]

Answer:

x = -3

y = 6

z = -5

Step-by-step explanation:

A) x + y + 2z = -7

B) -5z = 25

C) 3x - 3y - 6z = 3

B) -5z = 25

z = 25/-5

(z = -5)

A) x + y + 2(-5) = -7

x + y = -7 + 10

x + y = 3

(x = 3 - y)

C) 3x - 3y + 6(-5) = 3

3x - 3y + 30 = 3

3x - 3y = -30-3

3x - 3y = - 27

C) 3 (3-y) - 3y + 30 = 3

9 - 3y - 3y+ 30 = 3

-6y + 39 = 3

-6y = -39 + 3

y = -36/-6

(y = 6)

x + 6 = 3

x = 3 -6

(x = -3)

8 0
3 years ago
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