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gayaneshka [121]
3 years ago
10

Harriet paid $349.65 for 7 fruit trees. if each of the trees cost the same, what is the cost of one tree?

Mathematics
1 answer:
coldgirl [10]3 years ago
8 0
This is a division problem.
Divide 349.65 by 7
This is 49.95
Answer is $49.95


To check multiply 49.95 x 7= 349.65
Nipola_ling
2 years ago
x=\sqrt[7]{7}
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Your credit limit is $2,500 what is the max you should ever owe on this card?
lions [1.4K]

Answer: $2,000

To calculate the max amount you should owe, multiply the credit limit by 80%. $2,500 * 80% = 2,000

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3 years ago
Probabilities with possible states of nature: s1, s2, and s3. Suppose that you are given a decision situation with three possibl
amm1812

Answer:

1. P(s_1|I)=\frac{1}{11}

2. P(s_2|I)=\frac{8}{11}

3. P(s_3|I)=\frac{2}{11}

Step-by-step explanation:

Given information:

P(s_1)=0.1, P(s_2)=0.6, P(s_3)=0.3

P(I|s_1)=0.15,P(I|s_2)=0.2,P(I|s_3)=0.1

(1)

We need to find the value of P(s₁|I).

P(s_1|I)=\frac{P(I|s_1)P(s_1)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}

P(s_1|I)=\frac{(0.15)(0.1)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}

P(s_1|I)=\frac{0.015}{0.015+0.12+0.03}

P(s_1|I)=\frac{0.015}{0.165}

P(s_1|I)=\frac{1}{11}

Therefore the value of P(s₁|I) is \frac{1}{11}.

(2)

We need to find the value of P(s₂|I).

P(s_2|I)=\frac{P(I|s_2)P(s_2)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}

P(s_2|I)=\frac{(0.2)(0.6)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}

P(s_2|I)=\frac{0.12}{0.015+0.12+0.03}

P(s_2|I)=\frac{0.12}{0.165}

P(s_2|I)=\frac{8}{11}

Therefore the value of P(s₂|I) is \frac{8}{11}.

(3)

We need to find the value of P(s₃|I).

P(s_3|I)=\frac{P(I|s_3)P(s_3)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}

P(s_3|I)=\frac{(0.1)(0.3)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}

P(s_3|I)=\frac{0.03}{0.015+0.12+0.03}

P(s_3|I)=\frac{0.03}{0.165}

P(s_3|I)=\frac{2}{11}

Therefore the value of P(s₃|I) is \frac{2}{11}.

4 0
3 years ago
Select all of the following tables which represent y as a function of x.x 5 10 11y 3 9 15x 5 10 11y 3 9 9x 5 10 10y 3 9 15
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Answer:

Table 1 and 2 represent a function

Step-by-step explanation:

Given

<em>Table 1</em>

x 5 10 11

y 3 9 15

<em></em>

<em>Table 2</em>

x 5 10 11

y 3 9 9

<em>Table 3</em>

x 5 10 10

y 3 9 15

Required

Determine which of the tables represent that y is a function of x

For a relation to be a function; the x values must be unique.

In other words, each x value must not be repeated;

Having said that;

Analyzing Table 1

<em>Table 1</em>

x 5 10 11

y 3 9 15

<em></em>

Note that the x rows are unique as no value were repeated;

Hence, Table 1 is a function

<em>Table 2</em>

x 5 10 11

y 3 9 9

Note that the x rows are unique as no value were repeated;

Hence, Table 2 is a function

<em>Table 3</em>

x 5 10 10

y 3 9 15

Note that the x rows are not unique because 10 was repeated twice;

Hence, Table 3 is not a function

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postnew [5]
1.8 km >> 1,800 m
1,800 - 740 = 1,060 m
1,060 m >> 1.06 km
The shorter route is 1.06 km.
7 0
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