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arlik [135]
3 years ago
8

What is 1/8 in a decimal

Mathematics
2 answers:
sukhopar [10]3 years ago
7 0
To get the answer, divide 1 by 8
Which equals 0.125
And that is your answer.

Hope I Helped You!!! :-)

Have A Good Day!!!


vlabodo [156]3 years ago
6 0
This is an easy rule to use. Whenever you have a fraction divide the numerator into the denominator to find the percentage. It's easiest to do with a calculator. 
For example, 1/2 is 50%. We know that, but how did we get 50%?
1 divided by 2 is .5    All you have to do is add a zero.
1÷2=.5     ---->     50%
Now with your problem, all you have to do is apply the same rule.
1÷8= .125   Be careful though. This does NOT mean 125% This means 12.5% or if you want to round it, it's 13%. The only reason why is because wherever the number in the hundreds place is, that's where you add the decimal. This is because percentages are measured by 100. 
So the answer is 12.5% because 1 ÷ 8= .125 
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The least common denominator of 1/4 and 3/8?
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The length of a 3D rectangle is 8cm greater than the width and the height is half the length. A total of 108 cm of wire has been
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3 years ago
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What are the coordinates of the orthocenter of △JKL with vertices at J(−4, −1) , K(−4, 8) , and L(2, 8) ?
Sati [7]

<u>Answer-</u>

<em>The coordinates of the orthocenter of △JKL is (-4, 8)</em>

<u>Solution-</u>

The orthocenter is the point where all three altitudes of the triangle intersect. An altitude is a line which passes through a vertex of the triangle and is perpendicular to the opposite side.

For a right angle triangle, the vertex at the right angle is the orthocentre of the triangle.

Here we are given the three vertices of the triangle are  J(-4,-1), K(-4,8) and L(2,8)

If the triangle JKL satisfies Pythagoras Theorem, then triangle JKL will be a right angle triangle.

Applying distance formula we get,

JK^2= (-4+4)^2+ (8+1)^2=0+81=81\\\\KL^2= (-4-2)^2+ (8-8)^2=36+0=36\\\\JL^2= (-4-2)^2+(8+1)^2=36+81=117

As,

\Rightarrow 117=81+36

\Rightarrow JL^2=JK^2+KL^2

\Rightarrow \text{JKL is a right angle triangle}

\Rightarrow \angle K=90^{\circ}

Therefore, the vertex at K (-4, 8) is the orthocentre.

3 0
3 years ago
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