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2 years ago

What are rational numbers?

2 answers:

7 0

Answer: The numbers which can be expressed as a ratio of two integers where the denominator is not equal to zero

Step-by-step explanation:

Rational numbers are expressed in the form of $\frac{p}{q}$ where $q\neq 0$ . 'q' is the denominator in the above fraction.

The fractional form which is terminating or non-terminating recurring are considered as rational numbers.

The numbers 'p' and 'q' are the integers.

Integers are defined as number which is a proper number and not a fraction or decimal. All negative whole numbers are considered as integers.

Some Examples of Rational numbers: $\frac{5}{10}$ is a terminating fraction. $\frac{2}{3}$ is a non-terminating recurring fraction

Hence, the numbers which can be expressed as a ratio of two integers where the denominator is not equal to zero

zvonat [6]2 years ago

5 0

Answer:

I'm not 100% sure, but I think it's 3

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Mary spent a total of $322.78 for a party. She spent $200.66 on food, plus an additional $30.53 for each hour of the party. How

bulgar [2K]

Let h equal the length of the party in hours

200.66 + 30.53h = 322.78

now just solve for h :)
30.53h = 122.12
h = 4

so the party was 4 hours long

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2 years ago

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What's less than negative 12

KengaRu [80]

-13,-14,-15 etc... negative 11 is actually larger then negative 12 because it is a larger number. In terms of negatives, the number closest to 0 always the larger number

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3 years ago

M_1=3x, m 2 = 4x, m 3 = 2x, find x. 10 20 30 40

Julli [10]

Answer:

x=20

Step-by-step explanation:

3x+4x+2x = 180

9x =180

x = 20

note: brainliest would be appreciated.

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2 years ago

What is 2 + 2 wrong answers only

forsale [732]

Wrong answer: 2+2 is 13

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2 years ago

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Verify cotB+tanB=secBcscB

masya89 [10]

Hmm let me stab at this
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$\frac{1}{ \tan( \alpha ) } + \tan( \alpha ) \\ = \frac{1}{ \tan( \alpha ) } + \frac{ { \tan( \alpha ) }^{2} }{ \tan( \alpha ) } \\ = \frac{1 + { \tan( \alpha ) }^{2} }{ \tan( \alpha ) } \\ = \frac{ { \sec( \alpha ) }^{2} }{ \tan( \alpha ) }$
so then we get
$\sec( \alpha ) ( \frac{ \sec( \alpha ) }{ \tan( \alpha ) } ) \\ = \sec( \alpha ) ( \frac{ \frac{1}{ \cos( \alpha )} }{ \frac{ \sin( \alpha ) }{ \cos( \alpha ) } } ) \\ = \sec( \alpha ) ( \frac{1}{ \sin( \alpha ) } ) \\ = \sec( \alpha ) \csc( \alpha )$
vote brainliest if you like my answer!

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3 years ago