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2 years ago

What are rational numbers?

2 answers:

7 0

Answer: The numbers which can be expressed as a ratio of two integers where the denominator is not equal to zero

Step-by-step explanation:

Rational numbers are expressed in the form of $\frac{p}{q}$ where $q\neq 0$ . 'q' is the denominator in the above fraction.

The fractional form which is terminating or non-terminating recurring are considered as rational numbers.

The numbers 'p' and 'q' are the integers.

Integers are defined as number which is a proper number and not a fraction or decimal. All negative whole numbers are considered as integers.

Some Examples of Rational numbers: $\frac{5}{10}$ is a terminating fraction. $\frac{2}{3}$ is a non-terminating recurring fraction

Hence, the numbers which can be expressed as a ratio of two integers where the denominator is not equal to zero

zvonat [6]2 years ago

5 0

Answer:

I'm not 100% sure, but I think it's 3

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List a value of b that will cause 4x2 + bx + 25 = 0 to have one real solution

vlada-n [284]

Answer:

Step-by-step explanation:

If you take (2x+5) (2x+5) = 0

then 4x^2 + 20x +25 = 0

5 0

3 years ago

I need a little bit of help here ☹️

Grace [21]

-3(y+2)^2 - 5 + 6y
= -3(y^2 + 4y + 4) - 5 + 6y
= -3y^2 - 12y - 12 - 5 + 6y
= -y^2 - 6y - 17

Answer
(-1) y^2 + (-6) y + (-17)

3 0

3 years ago

What is the simplified version of 3\sqrt{135}

Aleonysh [2.5K]

Answer:

The simplified version of $\sqrt[3]{135}$ is $3\sqrt[3]{5}$ .

Step-by-step explanation:

The given expression is

$\sqrt[3]{135}$

According to the property of radical expression.

$\sqrt[n]{x}=(x)^{\frac{1}{n}}$

Using this property we get

$\sqrt[3]{135}=(135)^{\frac{1}{3}}$

$\sqrt[3]{135}=(27\times 5)^{\frac{1}{3}}$

$\sqrt[3]{135}=(3^3\times 5)^{\frac{1}{3}}$

$\sqrt[3]{135}=(3^3)^{\frac{1}{3}}\times (5)^{\frac{1}{3}}$ $[\because (ab)^x=a^xb^x]$

$\sqrt[3]{135}=3\times \sqrt[3]{5}$ $[\because \sqrt[n]{x}=(x)^{\frac{1}{n}}]$

$\sqrt[3]{135}=3\sqrt[3]{5}$

Therefore the simplified version of $\sqrt[3]{135}$ is $3\sqrt[3]{5}$ .

7 0

3 years ago

Read 2 more answers

I need help with these two questions!! I got 72° for Question 7, I don't know I need help with both of them!! PLEASE HELP!! :)

Nat2105 [25]

Answer:

7. 49

8. 10.4

Step-by-step explanation:

7) our hypotenuse is 8, and the side opposite the base of ladder and ground angle is 6, therefore we can use Sin

sin = opposite/hypotenuse

sin(x) = 6/8 = 3/4

sin-1(3/4) = 49

8) using the theorem that alternate exterior angles are congruent

the angle opposite side x is 30

tan = opposite/adjacent

tan(30) = x/18

x = 18tan(30) = 6√(3) = 10.4

you can also use 30-60-90 special right triangles.

the side opposite 30 is x

side opposite 60 is x√(3)

and side opposite 90 is 2x

3 0

3 years ago

How to write five and nine tenths in standard from

Trava [24]

5 9/10 .........................................

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2 years ago