What are rational numbers?

2 answers:

7 0

Answer: The numbers which can be expressed as a ratio of two integers where the denominator is not equal to zero

Step-by-step explanation:

Rational numbers are expressed in the form of $\frac{p}{q}$ where $q\neq 0$ . 'q' is the denominator in the above fraction.

The fractional form which is terminating or non-terminating recurring are considered as rational numbers.

The numbers 'p' and 'q' are the integers.

Integers are defined as number which is a proper number and not a fraction or decimal. All negative whole numbers are considered as integers.

Some Examples of Rational numbers: $\frac{5}{10}$ is a terminating fraction. $\frac{2}{3}$ is a non-terminating recurring fraction

Hence, the numbers which can be expressed as a ratio of two integers where the denominator is not equal to zero

zvonat [6]3 years ago

5 0

Answer:

I'm not 100% sure, but I think it's 3

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Identify the x-intercepts of the function below f(x)=x^2+12x+24

damaskus [11]

ANSWER:

x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

SOLUTION:

Given, $f(x)=x^{2}+12 x+24$ -- eqn 1

x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.

Now, let us find the zeroes using quadratic formula for f(x) = 0.

$X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here, for (1) a = 1, b= 12 and c = 24

$X=\frac{-(12) \pm \sqrt{(12)^{2}-4 \times 1 \times 24}}{2 \times 1}$

$\begin{array}{l}{X=\frac{-12 \pm \sqrt{144-96}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{48}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{16 \times 3}}{2}} \\\\ {X=\frac{-12 \pm 4 \sqrt{3}}{2}} \\ {X=\frac{2(-6+2 \sqrt{3})}{2}, \frac{2(-6-2 \sqrt{3})}{2}} \\\\ {X=(-6+2 \sqrt{3}),(-6-2 \sqrt{3})}\end{array}$