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sergey [27]
3 years ago
9

Our product is equal to 6+2 what factors are we

Mathematics
2 answers:
gregori [183]3 years ago
7 0
The you will use is 2 and 4
IceJOKER [234]3 years ago
6 0
The factors you would use would be 2 and 4
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Which of any of these Equation shows the relationship between Kevin's age x and his mothers age Y choose all that are correct 3x
KengaRu [80]

Answer:

b) y-3x = 1

c) 3x+1 = y

Step-by-step explanation:

I think you forgot to write a little part of the question. If your complete statment with this condition, i have the answer.

"Kevin said that if you triple his age the result will be 1 less than his mother age. Which of any of these Equation shows the relationship between Kevin's age x and his mothers age Y choose all that are correct

a) 3x-y=1

b) y-3x=1

c) 3x+1=Y

d) 3x=1-y"

you can write "the triple of this ages" as: 3x. and the result is y-1. That is:

3x = y-1

That equation can be rewrite as:

1. Passing -1 to the other side as +1 you will have: 3x+1=y. That is option c).

2. From last point  3x+1=y. Passing 3x to the other side as -3x you will have: y-3x=1. That is option b).

4 0
3 years ago
PLEASE HELP WHO EVER GET THIS RIGHT WILL MAKE U BRAINIEST
MrMuchimi

Answer: 150

Step-by-step explanation:

You got it right, just divide 300 by 2 :)

6 0
3 years ago
Read 2 more answers
Marley has read 112.5 pages of a book. By the end of today, she plans to have read at least a total of 360 pages. If she reads 4
e-lub [12.9K]
She will need 5 and a half hours. First step is to do 360-112.5 the pgs she read and her goal. then you'll get 247.5. To find how many hours you need to find the unit rate. so 247.5 divided by 45 is 5.5 hours. 

hope this helped. can u mark me as the brainiest answer
6 0
3 years ago
Derivative of sin3x using first principle
Vera_Pavlovna [14]

\displaystyle f(x)=\sin(3x)\\\\\\f'(x)=\lim_{h\to0}\dfrac{\sin(3(x+h))-\sin(3x)}{h}\\\\f'(x)=\lim_{h\to0}\dfrac{\sin(3x+3h)-\sin(3x)}{h}\\\\f'(x)=\lim_{h\to0}\dfrac{2\cos\left(\dfrac{3x+3h+3x}{2}\right)\sin\left(\dfrac{3x+3h-3x}{2}\right)}{h}\\\\f'(x)=\lim_{h\to0}\dfrac{2\cos\left(\dfrac{6x+3h}{2}\right)\sin\left(\dfrac{3h}{2}\right)}{h}\\\\f'(x)=\lim_{h\to0}\dfrac{2\cos\left(\dfrac{6x+3h}{2}\right)\sin\left(\dfrac{3h}{2}\right)}{\dfrac{3h}{2}}\cdot\dfrac{3}{2}

\displaystyle f'(x)=\lim_{h\to0}2\cos\left(\dfrac{6x+3h}{2}\right)\cdot\dfrac{3}{2}\\\\f'(x)=\lim_{h\to0}3\cos\left(\dfrac{6x+3h}{2}\right)\\\\f'(x)=3\cos\left(\dfrac{6x+3\cdot 0}{2}\right)\\\\f'(x)=3\cos\left(\dfrac{6x}{2}\right)\\\\f'(x)=3\cos(3x)

3 0
3 years ago
If the triangles in the figure are similar what is the length of side b?
kolezko [41]

Answer:

A 36

Step-by-step explanation:

We can determine the scale factor

From triangle ABC BC =9

                     DEF  EF = 90

We multiply by 10

The scale factor is 10

AC ( 10) = DF

We know DF = 360

b  * 10 = 360

Divide each side by 10

10b/10 = 360/10

b = 36

6 0
3 years ago
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