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sergey [27]
2 years ago
9

Our product is equal to 6+2 what factors are we

Mathematics
2 answers:
gregori [183]2 years ago
7 0
The you will use is 2 and 4
IceJOKER [234]2 years ago
6 0
The factors you would use would be 2 and 4
You might be interested in
Plz help<br> Don’t know which one it is?
ddd [48]

Answer:

 First option  6^\frac{1}{6} is the correct answer.

Step-by-step explanation:

Let us consider each part, we have number 6 inside all the roots.

First we have to find cube root of 6.

                    \sqrt[3]{6} =6^\frac{1}{3}

Now we have to find square root of this value.

                   \sqrt{6^\frac{1}{3}  } =(6^\frac{1}{3} )^\frac{1}{2} =6^\frac{1}{6}

So, first option  6^\frac{1}{6} is the correct answer.

3 0
3 years ago
In the equation |x+8| = 3 the center number is -8. true or false
jenyasd209 [6]

Answer:

False the center number is a postive 8

Step-by-step explanation:

7 0
2 years ago
8 multiplied by 3/4 divided by 3/3
bezimeni [28]
8 * 3/4

Multiply 8 by 4 to get 32 then divide 32 by 3 to get 3.6 repeating

3/3 is basically 1 so its still 3.6 

3.6 is  3 3/5

-XCalypso

~ Dont forget to rate, thank and vote brainliest answer! :D ~
5 0
3 years ago
Please I’m confused…
Anika [276]

Answer:

I believe it should be

4 : 1 : 200

Step-by-step explanation:

4 0
2 years ago
The mean number of children among a sample of 15 low-income households is 2.8. The mean number of children among a sample of 19
gtnhenbr [62]

Answer:

Step-by-step explanation:

Let's put the data as below:

n1=15    x1=2.8      s1=1.6       and s1²=2.56

n2=19   x2=2.4     s2=1.7        and s2²=2.89

alpha= 0.05

To test the hypothesis:

H0= There is no sufficient evidence that low income household have fewer children

H1=There is sufficient evidence that low income household have fewer children

Assume that population variances are equal.

the t-static for two samples,

t=\frac{x1-x2}{Sp\sqrt{\frac{1}{n1}-\frac{1}{n2} \\} } } ~t with min (n1-1,n2-1)df

The pooled variance estimate Sp equals:

Sp^{2}=\frac{(n1-1)s1^{2}+(n2-1)s2^{2}  }{n1+n2-2}

Sp²=2.7456

Sp=1.65699

Degrees of freedom=n1+n2-2=32

Under null hypothesis:

tcal=\frac{|2.8 - 2.4|}{1.6599\sqrt{\frac{1}{15}+\frac{1}{19}  } }

tcal=0.6989

The critical value ttab=2.0369 for alpha=0.05

So we reject our null hypothesis H0

So there is sufficient evidence that low income households have fewer children than high income households

6 0
3 years ago
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