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2 years ago

A theatre costs £63 plus a booking fee of 3%

Mathematics

1 answer:

s2008m [1.1K]2 years ago

3 0

Answer:

£64.89

Step-by-step explanation:

Cost of Ticket = £63

Booking Fee = 3% of £63 = 3/100*63 = £1.89

So, total cost of ticket = £64.89

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Solve log x − 1 16 = 4.

Reptile [31]

I hope this helps you

log(x-1)4^2=4

2.log (x-1)4=4

log (x-1)4=2

log (x-2)2^2=2

2log (x-1)2=2

log (x-1)2=1

[logab=y b=a^y]

b=2 a=x-1 y=1

2=(x-1)^1

x-1=2

x=3

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3 years ago

What is the greatest common divisor of 33489, 3948, and 3949

storchak [24]

33489 = 32×612

3948 = 22×3×7×47

3949 = 11×359

GCD = 1

33489 / 1 = 33489

3948 / 1 = 3948

3949 / 1 = 3949

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3 years ago

??!?!?!?!?!!?!?!?!!?!!!?!!!!?

Nikitich [7]

Answer:

The third option, a rational number

like 1/5 + 2.5 is still rational (but neither irrational nor whole/an integer)

it would be 0.2 + 2.5 = 2.7 btw

1/5 + 5/2

= 2/10 + 25/10

= 27/10

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3 years ago

Hey can anyone help me with 6th grade homework

Liula [17]

All depends on what help you need

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3 years ago

Read 2 more answers

Pls solve the simultaneous equation in the attachment.

siniylev [52]

Answer:

Part a) The solution is the ordered pair (6,10)

Part b) The solutions are the ordered pairs (7,3) and (15,1.4)

Step-by-step explanation:

Part a) we have

$\frac{x}{2}-\frac{y}{5}=1$ ----> equation A

$y-\frac{x}{3}=8$ ----> equation B

Multiply equation A by 10 both sides to remove the fractions

$5x-2y=10$ ----> equation C

isolate the variable y in equation B

$y=\frac{x}{3}+8$ ----> equation D

we have the system of equations

$5x-2y=10$ ----> equation C

$y=\frac{x}{3}+8$ ----> equation D

Solve the system by substitution

substitute equation D in equation C

$5x-2(\frac{x}{3}+8)=10$

solve for x

$5x-\frac{2x}{3}-16=10$

Multiply by 3 both sides

$15x-2x-48=30$

$15x-2x=48+30$

Combine like terms

$13x=78$

$x=6$

<em>Find the value of y</em>

$y=\frac{x}{3}+8$

$y=\frac{6}{3}+8$

$y=10$

The solution is the ordered pair (6,10)

Part b) we have

$xy=21$ ---> equation A

$x+5y=22$ ----> equation B

isolate the variable x in the equation B

$x=22-5y$ ----> equation C

substitute equation C in equation A

$(22-5y)y=21$

solve for y

$22y-5y^2=21$

$5y^2-22y+21=0$

Solve the quadratic equation by graphing

The solutions are y=1.4, y=3

see the attached figure

<em>Find the values of x</em>

For y=1.4

$x=22-5(1.4)=15$

For y=3

$x=22-5(3)=7$

therefore

The solutions are the ordered pairs (7,3) and (15,1.4)

3 0

3 years ago