Answer:
the hawk has flow 824.62 meters southwest of the mountain peak.
Step-by-step explanation:
In order to find the distance we need to use the Pythagoras theorem
d^2 = 800^2 + 200^2
d= 824.6 m
we can find the direction by using the eq for a tangent
he opposite side is 200 m and the adjacent side is 800m
tan theta = opposite / adjacent
theta = arc tan (800/200)
The hawk is at a distance of 824.6m flying at an angle 76 degrees NE of the mountain peak.
The final location will be southwest of the mountain peek.
a2+b2=c2
a = 200
b= 800
c = √(2002+8002) = 824.62
So the hawk has flow 824.62 meters southwest of the mountain peak.
Answer:

Step-by-step explanation:
Isolate the variable by dividing each side by factors that dont't contain the variable.



-8 -8

Divide both sides by 5.

Answer:
Please find the solution in the image attached below.
Step-by-step explanation:
Tcos60 -2T sin(90-theta) = 0
Tcos60 = 2T(cos theta)
cos 60 = 2cos theta
cos60 = 2cos theta
1/4 = cos theta
theta = 75.5
So the angle to the vertical = 90-75.5 = 14.5
S
Resolving perpendicular
Tsin60 + 2Tsin75.5 - 2g = 0
T(sin 60 + 2sin75.5) = 2g
T = 19.6/sin 60 + 2sin75.5
T = 19.6/1.936 + 0.866
T = 19.6/2.802 = 7.0N
Hope this helps!
To find the hypothenuse use Pythagorean theorem: 13²+5²=h²,
h=√13²+5²=13.93cm = hypothenuse.