Sixteen-twentyfive as a decimals
1 answer:
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Since we want to find the value of <em>k</em><em> </em>where the limit exists, set both equations equal to each other. Then substitute <em>x</em> = -1 in for each equation to find <em>k</em><em>.</em>
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1. Set both equations equal.
2. Substitute <em>x</em><em> </em>= -1.
3. Solve for <em>k</em><em> </em>by adding <em>k</em><em> </em>to both sides. Continue the process of solving the equation.
Thus, <em>k</em><em> </em>= -2. Check by graphing the function.
Answer:
y = 1
d = 4
Step-by-step explanation:
8y - 2d = 0 ---------------(I)
5y + 4d = 26 1/4
5y + 4d = 105/4 ------------------(II)
(I)*2 16y - 4d = 0
(II) <u>5y + 4d = 105/4</u> {add (I) &(II)}
21y = 105/4
Substitute y =1 in equation (I)
8*1 - 2d = 0
8 - 2d = 0
-2d = -8
d = -8/-2
d = 4
Answer:
{2, 8}
Step-by-step explanation:
We want to find x for ...
15 = 4|x -5| +3
12 = 4|x -5| . . . . subtract 3
3 = |x -5| . . . . . . divide by 4
±3 = x -5 . . . . . . show the meaning of absolute value
5 ±3 = x = {2, 8} . . . . . add 5
The values of x for which f(x) = 15 are 2 and 8.
