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Oxana [17]
3 years ago
8

What is the probability of rolling the sum of 5 or 8 on a pair of number cubes?

Mathematics
2 answers:
Tasya [4]3 years ago
7 0

|\Omega|=6^2=36\\|A|=\underbrace{4}_{\text{the sum is 5}}+\underbrace{5}_{\text{the sum is 8}}=9\\\\P(A)=\dfrac{9}{36}=\dfrac{1}{4}=25\%

butalik [34]3 years ago
5 0
The probability of rolling a 5 is 4/36 (reduced to 1/9) and the probability of rolling an eight is 5/36. Rolling either would be 9/36 (reduced to 1/4)
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Giselle wants to buy a condo that has a purchase price of $163,000. giselle earns $2,986 a month and wants to spend no more than
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The condo costs $163,000, earns $2,986 per month, spends no more than 25% of her income, then if she pays $33,000 for the down payment, the remaining amount would be $130,000. Since 20% of the initial cost is only $32,600, she can adjust her down payment to 20.25% of the initial cost so that the annual payments would be less.
6 0
4 years ago
Read 2 more answers
I need help with this problem asap
FinnZ [79.3K]

════════ ∘◦❁◦∘ ════════

<h3>Answer</h3>

a = 36

b = √3/5

════════════════════

<h3>Known </h3>

Adjuscent = 12√3

════════════════════

<h3>Question</h3>

Opposite = ?

Hypotenuse = ?

════════════════════

<h3>Way to do</h3>

• finding a - opposite

#use tan formula

tan(∅) = opposite / adjuscent

tan(60) = opposite / 12√3

opposite = tan(60) × 12√3

opposite = 36

•finding b - hypotenuse

#use cos formula

cos(∅) = adjuscent / hypotenuse

cos(60) = 12√3 / hypotenuse

hypotenuse = 12√3 : cos(60)

hypotenuse = √3/5

════════════════════

3 0
3 years ago
What is the length (in cm) of a rectangle with width 14 cm and area 168² cm​
kati45 [8]

Answer:

12

Step-by-step explanation:

Area = length * width

length = area ÷ width

4 0
3 years ago
Q
kifflom [539]
7.3 is your answer my guy
8 0
3 years ago
Answer the thing on screen. Make sure to use the right &lt; or &gt; thing
BlackZzzverrR [31]

Answer:

12 \leq v

Step-by-step explanation:

first you subtract 7 from 7 and 12

19\leq v+ 7\\-7           -7

then you get 19 \leq v

(btw the variable always goes first with these problems)

so the final answer would be v \geq 12

3 0
3 years ago
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