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3 years ago

What is the probability of rolling the sum of 5 or 8 on a pair of number cubes?

2 answers:

7 0

$|\Omega|=6^2=36\\|A|=\underbrace{4}_{\text{the sum is 5}}+\underbrace{5}_{\text{the sum is 8}}=9\\\\P(A)=\dfrac{9}{36}=\dfrac{1}{4}=25\%$

butalik [34]3 years ago

5 0

The probability of rolling a 5 is 4/36 (reduced to 1/9) and the probability of rolling an eight is 5/36. Rolling either would be 9/36 (reduced to 1/4)

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Find the measure of angle A. 1+ 38 x + 68 A) 30° C) 26° B) 35° D) 60°

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3 years ago

Translate this sentence into an equation.

Katarina [22]

Answer:

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3 years ago

Use synthetic division to find P (-10) for P(x)=2x^3+14x^2-58x

Savatey [412]

The polynomial remainder theorem states that the remainder upon dividing a polynomial $p(x)$ by $x-c$ is the same as the value of $p(c)$ , so to find $p(-10)$ you need to find the remainder upon dividing

$\dfrac{2x^3+14x^2-58x}{x+10}$

You have

..... | 2 ... 14 ... -58
-10 | ... -20 ... 60
--------------------------
..... | 2 ... -6 .... 2

So the quotient and remainder upon dividing is

$\dfrac{2x^3+14x^2-58x}{x+10}=2x-6+\dfrac2{x+10}$

with a remainder of 2, which means $p(-10)=2$ .

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3 years ago

Please answer answer question

Sophie [7]

Answer:

The correct answer is

Step-by-step explanation:

11 square centimeters.

Hope this helps....

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8 0

3 years ago

Read 2 more answers

Find the first 4 terms in the expansion of ( 1 + x 2 ) 8. Use your answer to find the value of ( 1.01 ) 8

anyanavicka [17]

(1+x^2)^8

=(1+8x^2+8*7/(1*2)x^4+8*7*6/(1*2*3)x^6+8*7*6*5/(1*2*3*4)x^8+....)

=1+8x^2+28x^4+56x^6+70x^8+....)

For x<1, higher power terms diminish in value, hence we can approximate powers of numbers.

1.01=(1+0.1^2) => x=0.1 in the above expansion

(1.01)^8

=1+8(0.1^2)+28(0.1^4)+56(0.1^6) [ limited to four terms, as requested]

=1+0.08+0.0028+0.000056 (+0.00000070)

=1.082856 (approximately)

7 0

3 years ago