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ddd [48]
4 years ago
7

At the Denver zoo, adult admission is $15 and children's is $9 a group of 12 people go to the zoo. Their total admission was $15

0. Set up a system of linear equations and solve
Mathematics
1 answer:
Natasha2012 [34]4 years ago
3 0

Answer:

The number of adults admitted at the zoo=7

The number of children admitted at the zoo=5

Step-by-step explanation:

a). Determine first expression

Let the number of each group be as follows;

adults=a

children=c

total number of people=12

This can be expressed as;

number of people=number of children+number of adults

replacing;

a+c=12...equation 1

b). Determine the second expression

Let the total cost be expressed as shown;

total cost=(cost per child×number of children)+(cost per adult×number of adults)

where;

total cost=$150

cost per child=$9

number of children=c

cost per adult=$15

number of adults=a

replacing;

(15×a)+(9×c)=150

15 a+9 c=150...equation 2

c). Combine equation 1 and 2 and solve simultaneously

1(15 a+9 c=150)

-

9(a+c=12)=9 a+9 c=108

(15 a-9 a)+(9 c-9 c)=(150=108)

6 a=42

a=42/6

a=7

replacing the value for a in equation 1

7+c=12

c=12-7=5

The number of adults admitted at the zoo=7

The number of children admitted at the zoo=5

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ANSWER THE QUESTIONS PLEASE IT IS ON BEARING
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9514 1404 393

Answer:

  (i) x° = 70°, y° = 20°

  (ii) ∠BAC ≈ 50.2°

  (iii) 120

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Step-by-step explanation:

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  x = 70

The angle marked y° is the supplement to the one marked 160°.

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(ii) The triangle interior angle at B is x° +y° = 70° +20° = 90°, so triangle ABC is a right triangle. With respect to angle BAC, side BA is adjacent, and side BC is opposite. Then ...

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  ∠BAC = arctan(1.2) ≈ 50.2°

__

(iii) The bearing of C from A is the sum of the bearing of B from A and angle BAC.

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(iv) The bearing of A from C is 180 added to the bearing of C from A:

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The three-digit bearing of A from C is 300.

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