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3 years ago

9

Can someone answer this for me pls

1 answer:

bezimeni [28]3 years ago

5 0

Answer: Lin is the most consistent and I would want to have them on my team.

Why is this? Because their dots are more clustered together compared to the other distributions. Elena may have made the most shots (9) at one point, but her data set is very spread out and more unpredictable. The more spread out a data set is, the higher the variance and standard deviation. The range is also affected by how spread out the data set is since

range = max - min

So in a rough sense, the range can be used to estimate the variance and standard deviation. Though more accurate formulas are usually the better way to go.

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23.5584557678 rounded to the nearest hundredth

hram777 [196]

23.5584557678 = 23.56 <span>rounded to the nearest hundredth

hope it helps</span>

3 0

2 years ago

I need Help on 1-13 PLEASE ANSWER ASAP & QUICKLY I REALLY NEED YOUR HELP!! I don't accept: i don't knows people trying to he

Amanda [17]

1. >
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4 0

2 years ago

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Calculate the sample mean and sample variance for the following frequency distribution of heart rates for a sample of American a

spin [16.1K]

Answer:

$Mean = 68.9$

$s^2 =18.1$ --- Variance

Step-by-step explanation:

Given

$\begin{array}{cccccc}{Class} & {51-58} & {59-66} & {67-74} & {75-82} & {83-90} \ \\ {Frequency} & {6} & {3} & {11} & {13} & {4} \ \end{array}$

Solving (a): Calculate the mean.

The given data is a grouped data. So, first we calculate the class midpoint (x)

For 51 - 58.

$x = \frac{1}{2}(51+58) = \frac{1}{2}(109) = 54.5$

For 59 - 66

$x = \frac{1}{2}(59+66) = \frac{1}{2}(125) = 62.5$

For 67 - 74

$x = \frac{1}{2}(67+74) = \frac{1}{2}(141) = 70.5$

For 75 - 82

$x = \frac{1}{2}(75+82) = \frac{1}{2}(157) = 78.5$

For 83 - 90

$x = \frac{1}{2}(83+90) = \frac{1}{2}(173) = 86.5$

So, the table becomes:

$\begin{array}{cccccc}{x} & {54.5} & {62.5} & {70.5} & {78.5} & {86.5} \ \\ {Frequency} & {6} & {3} & {11} & {13} & {4} \ \end{array}$

The mean is then calculated as:

$Mean = \frac{\sum fx}{\sum f}$

$Mean = \frac{54.5*4+62.5*3+70.5*11+78.5*13+86.5*4}{6+3+11+13+4}$

$Mean = \frac{2547.5}{37}$

$Mean = 68.9$ -- approximated

Solving (b): The sample variance:

This is calculated as:

$s^2 =\frac{\sum (x - \overline x)^2}{\sum f - 1}$

So, we have:

$s^2 =\frac{(54.5-68.9)^2+(62.5-68.9)^2+(70.5-68.9)^2+(78.5-68.9)^2+(86.5-68.9)^2}{37 - 1}$

$s^2 =\frac{652.8}{36}$

$s^2 =18.1$ -- approximated

5 0

2 years ago

What is the area of this figure?<br><br><br><br> Enter your answer in the box.<br><br> ( )

aksik [14]

Answer:

88 square units

Step-by-step explanation:

7 0

2 years ago

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in a football game, a touchdown with an extra point is worth 7 points and a field goal is worth 3 points. Suppose that in a game

Leokris [45]

1 and 2 are less then 3

4=3+1 but you cant get 1 from 7 or 3 so 4 is impossible. So is 5, 6, 8, and 20.

Bolded numbers are answers.

5 0

2 years ago

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