Which of equation represents a function? A. x2 + y2 = 9 B. {(4, 2), (4, –2), (9, 3), (9, –3)} C. x = 4. 2x + y = 5

1 answer:

3 0

The answer to your questions is B. {(4, 2), (4, –2), (9, 3), (9, –3)} because you don't have a repeat of a number the X side which is your output. I hope that this is the answer that you were looking for and it has helped you.

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The width of a triangle is six more than twice the height. The area of the triangle is 88in2. Find the height and base of the tr

malfutka [58]

For this case we have that by definition, the area of a triangle is given by:

$A = \frac {b * h} {2}$

Where:

b: It is the base of the triangle

h: It is the height of the triangle

According to the statement data we have:

$b = 6 + 2h$

Substituting we have:

$88 = \frac {(6 + 2h) * h} {2}\\176 = 6h + 2h ^ 2\\2h ^ 2 + 6h-176 = 0$

We divide between 2 on both sides:

$h ^ 2 + 3h-88 = 0$

We factor by looking for two numbers that, when multiplied, are obtained -88 and when added together, +3 is obtained.

These numbers are +11 and -8.

$(h + 11) (h-8) = 0$

We have two roots:

$h = -11\\h = 8$

We choose the positive value.

Thus, the base of the triangle is: $b = 6 + 2 (8) = 22$

Answer:

The base of the triangle is 22 units.

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What happens to the area of a circle when the radius is doubled? (1 point) it is doubled?

Alina [70]

I think the circle would grow bigger into an oval.

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3 years ago

For circle O, mCD=125° and m

Burka [1]

CA is a diameter of the circle, so $m\widehat{AC}=180^\circ$ , which means $m\angle AOB=m\angle AOD=m\widehat{AD}=180^\circ-m\widehat{CD}=55^\circ$ . Then $m\boxed{\angle ABO}=90^\circ-55^\circ=35^\circ$ .

This means $m\angle CBO=55^\circ-35^\circ=20^\circ$ . Also, if $m\angle AOB=55^\circ$ , then $m\angle BOC=180^\circ-55^\circ=125^\circ$ , which in turns tells us that $m\boxed{\angle BCO}=180^\circ-20^\circ-125^\circ=35^\circ$ .