Question

The axis of symmetry for the graph of the function f(x)=3x2+bx+4 is x = 3. What is the value of b?

Answer 1

Answer:

A)-18

Step-by-step explanation:

Given a quadratic equation of the form $y=ax^2+bx+c$, the axis of symmetry is determined by the formula $x=-\frac{b}{2a}$.

If the axis of symmetry of the equation: $f(x)=3x^2+bx+4$ is 3, then:

a=3, b=?, x=3

$x=-\frac{b}{2a}\\3=-\frac{b}{2*3}\\b=-6X3=-18$

The correct option is A.

Answer 2

Answer:

-9

Step-by-step explanation:

it's B on edg