Answer:
Expressions are not equivalent
Step-by-step explanation:
Given expressions are:
Putting w=1 in both expressions
![4(3w+4)\\=4[3(1)+4]\\=4(3+4)\\=4(7)\\=28\\\\16w+12\\=16(1)+12\\=16+12\\=28](https://tex.z-dn.net/?f=4%283w%2B4%29%5C%5C%3D4%5B3%281%29%2B4%5D%5C%5C%3D4%283%2B4%29%5C%5C%3D4%287%29%5C%5C%3D28%5C%5C%5C%5C16w%2B12%5C%5C%3D16%281%29%2B12%5C%5C%3D16%2B12%5C%5C%3D28)
Both expression have value 28 on w=1
Putting w=3 in both expressions
![4(3w+4)\\=4[3(3)+4]\\=4(9+4)\\=4(13)\\=52\\\\16w+12\\=16(3)+12\\=48+12\\=60](https://tex.z-dn.net/?f=4%283w%2B4%29%5C%5C%3D4%5B3%283%29%2B4%5D%5C%5C%3D4%289%2B4%29%5C%5C%3D4%2813%29%5C%5C%3D52%5C%5C%5C%5C16w%2B12%5C%5C%3D16%283%29%2B12%5C%5C%3D48%2B12%5C%5C%3D60)
Both expression have different values at w=3
Hence, in order for the expressions to be equivalent they both should produce same value on w=3 too.
So, it can be concluded that both expressions are not equivalent ..
A feature of every linear function is that the slope is the same no matter where you are on the line. When given a table of data that you suspect might represent a linear function the slope manifests itself as a constant common difference between successive y -values.
A is the answer as in both cases E is 90 degrees
Answer:
the student messed up at the point of adding 5 to I5, they subtracted instead and got 2x=I0 which would mean x=5. when instead they should've added 5 and got 2x=20 and got x=I0
