Question

The point slope form of the equation of the line that passes through (-5,-1) and (10,-7) is y+7=-2/5(x-10). what is the standard form of the equation for this line?
A. 2x-5y=-15
B. 2x-5y=-17
C. 2x+5y=-15
D. 2x+5y=-17​

Answer 1

Option C

The standard form of the equation for y + 7 = -2/5(x - 10) is 2x + 5y = -15.

Solution:

Need to determine standard form of equation of line passing through points (-5, -1) and (10, -7) and having slope form as  $y+7=-\frac{2}{5}(x-10)$

Standard form of equation of line is such that terms having variables are on left hand side and constant terms on right hand side.

So let’s simplify given slope form.

$y+7=-\frac{2}{5}(x-10)$

On opening the brackets we get

$y+7=\frac{-2 x+20}{5}$

=> 5(y + 7) = -2x +20

=> 5y + 2x = 20 – 35

=> 2x +5y = -15

Hence the standard form is 2x + 5y = -15.