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Tanya [424]
2 years ago
13

If f(x)=6x-4, what is f(x) when x = 8

Mathematics
2 answers:
dezoksy [38]2 years ago
6 0
X44 because when multiple 6x8 =48 subtracted 4
gtnhenbr [62]2 years ago
3 0
F(x)= 6x-4
f(x)=6*8-4
f(x)=48-4
f(x)=44
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In 1999 bus fare in atlanta was 4.70.In 1979 the fare was 2/5 of the fare in 1999 what was the fare in 1979
Gennadij [26K]

Answer : 1.96 was the fare in 1979.

Explanation :

Bus fare in Atlanta in 1999 =4.70

\text{As we have given that in 1979 the fare was } \frac{2}{5} \text{ of the fare in 1999.}

\text{Bus fare in Atlanta in 1979=} \frac{2}{5}\times 4.70

Bus fare in Atlanta in 1979 is given by

\frac{2\times 4.70}{5}\\\\=\frac{9.80}{5}\\\\=1.96

∴ 1.96 was the fare in 1979.




3 0
2 years ago
Read 2 more answers
The sum of two numbers is odd. Can the quotient of the two numbers be an odd number?
Natalka [10]

Answer: No.

Step-by-step explanation:

I guess that here we have the statement:

If the sum of two numbers is odd----> can their quotient be an odd number?

first, for n an integer number, we have that:

an odd number can be written as 2n + 1

an even number can be written as 2n.

The sum of two numbers is only odd if one of them is odd and the other even.

Then we have a number that is 2n and other that is 2k + 1, for n and k integer numbers.

Now, let's see if the quotient can also be an odd number.

One way to think this is:

There is an odd number such that when we multiply it by another odd number, the result is an even number?

no, and i can prove it as:

let 2k + 1 be an odd number, and 2j + 1 other.

the product is:

(2k + 1)*(2j + 1) = 2*(2*k*j + k + j) + 1

and as k and j are integers, also does 2*k*j + k + j, so:

2*(2*k*j + k + j) + 1 is an odd number.

This says that the product of two odd numbers is always odd, then we never can have that the quotient between an even number and an odd number is odd.

4 0
3 years ago
11. There are a total of 30 puzzle pieces. Three
natulia [17]

Answer: 2

Step-by-step explanation:

5-3=2

30-5=15

6 0
2 years ago
Read 2 more answers
. Consider the leading term of the polynomial function. What is the end behavior of the graph? Describe the end behavior and pro
QveST [7]
Because this is a fifth degree polynomial, it's an odd function.  Odd functions have one tail go up and the other down.  Because the leading coefficient is a negative number, 3 to be exact, the left one goes up and the right goes down.
3 0
3 years ago
Product FIFO LIFO
Julli [10]

Answer:

The null hypo would be the difference is greater than 0

so the alternate hypothesis would be less than or equal to 0

H1: µd ≤ 0

8 0
3 years ago
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