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emmasim [6.3K]
3 years ago
9

Hey so i have an easy question (so the mods don't get mad for me giving away points)

Mathematics
2 answers:
professor190 [17]3 years ago
8 0

Answer:315

Step-by-step explanation:

Kruka [31]3 years ago
6 0
315 and celebrate 4th of july
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Just answer the top answer please and thank you
luda_lava [24]

Answer:

C. 75

Step-by-step explanation:

6 0
3 years ago
What is exactly the relation between a Rhombus, rectangle, parallelogram, and square explain please i will mark brainliest only
ch4aika [34]

Any rhombus is a parallelogram, but not the other way around. If you were to make a Venn Diagram, the "rhombus" portion is entirely inside the set of "parallelograms".

The same can be said about rectangles as well. Any rectangle is a parallelogram, but not the other way around.

If we overlapped the region of rectangles and rhombuses, then we form the region for squares. A square is a combination of a rhombus and a rectangle.

Any square has all four sides the same length (property of a rhombus) and all angles equal to 90 (property of a rectangle). Since a square inherits properties of a rectangle and rhombus, it automatically makes any square a parallelogram.

Check out the venn diagram below.

5 0
2 years ago
Read 2 more answers
I also need help with this one
solmaris [256]
The amount of pizza Mark would have is
\frac{1}{6}  +  \frac{1}{4}
Find the common denominators first. 2/12 + 3/12 = 5/12. Two slices of the 6 slice pizza is 1/3 or 4/12.
6 0
3 years ago
If y varies directly as (x+3) and inversely as (x-3) and y=21 when x=4, what is the equation for y in terms of x?
igor_vitrenko [27]
\bf \qquad \qquad \textit{double proportional variation}
\\\\
\begin{array}{llll}
\textit{\underline{y} varies directly with \underline{x}}\\
\textit{and inversely with \underline{z}}
\end{array}\implies y=\cfrac{kx}{z}\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad  variation
\end{array}\\\\
-------------------------------\\\\

\bf \textit{\underline{y} varies directly as (x+3) and inversely as (x-3)}\implies y=\cfrac{k(x+3)}{x-3}
\\\\\\
\textit{we also know that }
\begin{cases}
y=21\\
x=4
\end{cases}\implies 21=\cfrac{k(4+3)}{4-3}\implies 21=\cfrac{k(7)}{1}
\\\\\\
\cfrac{21}{7}=k\implies 3=k\qquad thus\qquad \qquad \boxed{y=\cfrac{3(x+3)}{x-3}}
6 0
3 years ago
PLEASE HELP ME THIS IS DUE BY 1 P.M AND I REALLY NEED HELP
irga5000 [103]
It is not factored completely because it was only factored by 3ab but it could have been factored by 6a²b

6a²b(a+6+8a²)
5 0
2 years ago
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