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emmasim [6.3K]
3 years ago
9

Hey so i have an easy question (so the mods don't get mad for me giving away points)

Mathematics
2 answers:
professor190 [17]3 years ago
8 0

Answer:315

Step-by-step explanation:

Kruka [31]3 years ago
6 0
315 and celebrate 4th of july
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Given the following, what is the probability of choosing an purple marble and flipping tails?
MrMuchimi
Your answer is correct!! 2/3
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3 years ago
Solve each equation. Check your solution. <br> A) -6a=36<br> B) -9d=-72
vovikov84 [41]
A) -6a = 36

Divide both sides by -6 so that (a) is isolated.

a = -6

Check by plugging in -6 for a.

-6a=36

-6(-6)=36

36=36

So, a=-6

B) -9d=-72

Divide both sides by -9.

d = -72/-9

d = 8

Check work by plugging in 8 for d.

-9d=-72

-9(8)=-72

-72=-72

So, d=8

~Hope I helped!~
3 0
3 years ago
What is the size of the picture reducing it by 1/25 original size 75 by 50
Svetradugi [14.3K]
50/1 * 1/25 = 50/25 = 2

75/1 * 1/25 = 75/25 = 3

The reduced painting is 2cm x 3cm
5 0
3 years ago
Which are the solution of x2=-5x+8
yawa3891 [41]

rewrite the equation set = to 0.

x^2 + 5x - 8 = 0

The quadratic will not factor so you have to use the quadratic formula.

x = (-b + - sqrt(b^2 - 4ac))/2a

x = (5 + - sqrt(25 - 4* 1* -8))/2

x = (5 + - sqrt 57)/2


The x2is not the same as 2x. It is x^2. X tot he second power which makes the problem a quadratic equation. You cannot combine the terms x^2 and -5x because they so not have the same power.

4 0
3 years ago
Let f be a differentiable function such that f(3)=15, f(6)=3, f ' (3)= -8, and f ' (6)= -2. The function g is differentiable and
Ray Of Light [21]

Answer:

A. g'(3)=-\frac{1}{2}

Step-by-step explanation:

We have been given that f be a differentiable function such thatf(3)=15, f(6)=3, f'(3)= -8, and f'(6)= -2. The function g is differentiable and g(x)= f^{-1} (x) for all x.

We know that when one function is inverse of other function, so:

g(f(x))=x

Upon taking derivative of both sides of our equation, we will get:

g'(f(x))*f'(x) =1

g'(f(x))=\frac{1}{f'(x)}

Plugging x=6 into our equation, we will get:

g'(f(6))=\frac{1}{f'(6)}

Since g(x)= f^{-1} (x), then g'(f(6))=g'(3).

g'(3)=\frac{1}{f'(6)}

Since we have been given that f'(6)= -2, so we will get:

g'(3)=\frac{1}{-2}

g'(3)=-\frac{1}{2}

Therefore, g'(3)=-\frac{1}{2} and option A is the correct choice.

8 0
3 years ago
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