All categories

2 years ago

Hey so i have an easy question (so the mods don't get mad for me giving away points)

Mathematics

2 answers:

professor190 [17]2 years ago

8 0

Answer:315

Step-by-step explanation:

Kruka [31]2 years ago

6 0

315 and celebrate 4th of july

You might be interested in

Lydia read 1/5 of her book last week. this week she read 3 times as much as she read last week. write an expression to show how

bogdanovich [222]

1/5 × 3 + 1/5 = y

4/5 = y

8 0

2 years ago

Write the phrase as an expression. Then evaluate the expression when y=20 . the quotient of 40 and the difference of a number y

nlexa [21]

Answer:

Write the phrase as an expression. Then evaluate the expression when y=20 . the quotient of 40 and the difference of a number y and 16 Expression: When y=20, the value of the expression is

7 0

2 years ago

Mark has fourteen dollars and Dan has sixteen dollars. They both have spent five dollars at the mall. Mark still has less money

tino4ka555 [31]

Answer: yes

Step-by-step explanation: Because he had a lower number to begin with and they both spent the same amount of money

4 0

2 years ago

A rectangle that is 2 inches by 3 inches has been scaled by a factor of 7.

loris [4]

Answer:

$New\ Lengths = (14,21)$

$New\ Scale\ Factor = \frac{1}{7}$

Step-by-step explanation:

Given

Rectangle:

Length = 2 in

Width = 3 in

Scale Factor = 7

Solving (a):

The side lengths of the new scale is calculated as follows;

New Lengths = Old Lengths * Scale Factor

$New\ Lengths = (2,3) * 7$

$New\ Lengths = (2 * 7,3* 7)$

$New\ Lengths = (14,21)$

Solving (b): To go back to the original length

Given that the initial scale factor is 7;

The new scale factor is the reciprocal of the old factor;

Hence;

$New\ Scale\ Factor = \frac{1}{7}$

6 0

3 years ago

A fast food restaurant executive wishes to know how many fast food meals teenagers eat each week. They want to construct a 99% c

Lana71 [14]

Answer:

The minimum sample size required to create the specified confidence interval is 2229.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.99}{2} = 0.005$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.005 = 0.995$ , so $z = 2.575$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

What is the minimum sample size required to create the specified confidence interval

This is n when $M = 0.06, \sigma = 1.1$

$0.06 = 2.575*\frac{1.1}{\sqrt{n}}$

$0.06\sqrt{n} = 2.575*1.1$

$\sqrt{n} = \frac{2.575*1.1}{0.06}$

$(\sqrt{n})^{2} = (\frac{2.575*1.1}{0.06})^{2}$

$n = 2228.6$

Rounding up

The minimum sample size required to create the specified confidence interval is 2229.

7 0

2 years ago