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3 years ago

44 mi/h=_________ yd/min

1 answer:

5 0

We need to convert the miles to yards, and the hour to minutes. Then calculate as follows:
$44\ mi/hr=\frac{44\times1760}{60}=1,290.67\ yds/min.$

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Can someone please help me!!! ASAP!! SOS!!!.... =( find the following using the given polygon

Phantasy [73]

Answer:
n = 6
a = 6 mm
r = 5.19615 mm
R = 6 mm
A = 93.53 mm2 times $3 = $280.59
P = 36 mm
x = 120 °
y = 60 °

r = inradius (apothem)
R = circumradius
a = side length
n = number of sides
x = interior angle
y = exterior angle
A = area
P = perimeter
π = pi = 3.14159...
√ = square root

3 0

4 years ago

Need help... post question in comments once someone answers

Ksenya-84 [330]

What's up? How can I help?

3 0

4 years ago

Solve the system<br> 3x+5y=2<br> -9x-15=-9

Dennis_Churaev [7]

Answer:

x=-2/3

y=4/5

Step-by-step explanation:

solve for the first variable in one of the equations and then substitute the result into the other equation

3 0

3 years ago

Find the LCM of k^2 + 3k + 2 and 2k^2 + 14k + 20.

Airida [17]

Answer:

C. 2(k +2)(k +5)(k +1)

Step-by-step explanation:

The LCM will be the product of unique factors.

$(k^2 + 3k + 2)=(k+1)(k+2)\\(2k^2 + 14k + 20)=2(k+2)(k+5)$

The unique factors are 2, (k+1), (k+2), (k+5), so the LCM is their product:

2(k+1)(k+2)(k+5) . . . . matches choice C

3 0

3 years ago

Solve each quadratic equation by completing the square. 6. x2 + 2x = 8 7. x2 - 6x = 16 8. x2 - 18x = 19 9. x2 + 3x = 3 10. x2 +

Andrei [34K]

Lets get started :)

These questions have asked us to solve by completing the square.
How do we? I have attached a picture, which will explain

6. x² + 2x = 8
→ b is the coefficient of x, which is 2
→ We take half of 2 and square it. Then, we add it to either side

x² + 2x $+ (\frac{2}{2} )^2 = 8 + ( \frac{2}{2})^2$
x² + 2x + 1 = 8 + 1
( x + 1 )( x + 1 ) = 9
( x + 1 )² = 9
$\sqrt{( x + 1 )^2} = \sqrt{9}$
x + 1 = + 3 or x + 1 = - 3
x = 2 or x = - 4

7. x² - 6x = 16

→ We do the same thing we did in the previous question

x² - 6x + $(\frac{6}{2})^2 = 16 + (\frac{6}{2})^2$
x² - 6x + 9 = 16 + 9
(x - 3)² = 25
$\sqrt{(x-3)^2} = \sqrt{25}$
x - 3 = + 5 or x - 3 = - 5
x = 8 or x = - 2

8. x² - 18x = 19

x² - 18x + $( \frac{18}{2} )^2 = 19 + ( \frac{18}{2})^2$
x² - 18x + 81 = 19 + 81
( x - 9 )( x - 9 ) = 100
( x - 9 )² = 100
$\sqrt{(x-9)^2} = \sqrt{100}$
x - 9 = + 10 or x - 9 = -10
x = 19 or x = - 1

9. x² + 3x = 3

x² + 3x + $( \frac{3}{2} )^2 = 3 + (\frac{3}{2} )$
$x^2 + 3x + \frac{9}{4} = 3 + \frac{9}{4}$
$x^{2} + 3x + \frac{9}{4} = \frac{21}{4}$
$(x^2 + \frac{3}{2} ) ( x^2 + \frac{3}{2} ) = \frac{21}{4}$
$( x^2 + \frac{3}{2} )^2 = \frac{21}{4}$
$\sqrt{ x^2 + \frac{3}{2} } = \sqrt{ \frac{21}{4} }$
x + $\frac{3}{2}$ = + $\frac{ \sqrt{21} }{2}$ or x + $\frac{3}{2} = - \frac{ \sqrt{21} }{2}$
x = $\frac{-3+ \sqrt{21} }{2}$ or x = $\frac{-3 - \sqrt{21}}{2}$

7 0

4 years ago