Question

What is an equation for the line with slope 2/3 and y-intercept 9?

Answer 1

Y=mx+b
m=slope
b=yintercept

given
slope=2/3=m
yintercept=9=b

y=2/3x+9

Answer 2

Answer:

$y=\frac{2}{3}x+9$

Step-by-step explanation:

We can describe a line using the following equation :

$y=ax+b$

Where ''a'' and ''b'' are real numbers.

In the equation, the number ''a'' is the slope of the line. If we want a line with slope $\frac{2}{3}$ ⇒

$y=\frac{2}{3}x+b$

The intersection of a line with the y-axis can be calculated replacing $x=0$ in the equation ⇒

$y=(\frac{2}{3}).(0)+b\\y=b$

The interception is the real number ''b''. We want that interception to be 9

⇒

$y=\frac{2}{3}x+9$ is the equation of the line with slope $\frac{2}{3}$ and that intersects the y-axis at the point $(0,9)$