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vitfil [10]
2 years ago
15

Jason went shopping.

Mathematics
2 answers:
Anvisha [2.4K]2 years ago
8 0
If u r not interested in the explanation jump to the end ***

1. We assume, that the number 53.55 is 100% - because it's the output value of the task. 
2. We assume, that x is the value we are looking for. 
3. If 53.55 is 100%, so we can write it down as 53.55=100%. 
4. We know, that x is 15% of the output value, so we can write it down as x=15%. 
5. Now we have two simple equations:
1) 53.55=100%
2) x=15%
where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:
53.55/x=100%/15%
6. Now we just have to solve the simple equation, and we will get the solution we are looking for.

7. Solution for what is 15% of 53.55

53.55/x=100/15
(53.55/x)*x=(100/15)*x       - we multiply both sides of the equation by x
53.55=6.6666666666667*x       - we divide both sides of the equation by (6.6666666666667) to get x
53.55/6.6666666666667=x 
8.0325=x 
x=8.0325
*******
now we have: 
15% of 53.55=8.0325.
the total price was 53.55+8.0325=61.5825 the price before the discount
61.5825 - 38 = 23.5825 ~ 23.58
Contact [7]2 years ago
4 0

Answer:

£25

Step-by-step explanation:

In this question, we are asked to calculate the amount that a discounted purchase cost before the discount was applied.

From the question, we were made to know that 53.55 included the discount. Now if 15% was the price of the discount, this means what she paid was 85% and this is equivalent to the value 53.55

since we do not know the total price before the discount, let’s call that x.

This means that;

85/100 * x = 53.55

85x = 53.55 * 100

85x = 5355

x = 5355/85

x = £63

Now we were made to know that the trainers were priced at £38 before the discount, the price of the watch before the discount is thus £63 - £38 = $25

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Arada [10]

Answer:

21

Step-by-step explanation:

If the number is a multiple of 3 but not of 6, the number must be odd. The only odd multiple of 3 between 17 and 25 is 21, meaning that this is the answer. Hope this helps!

8 0
3 years ago
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For each container of tea, McKenzie uses 16 tea bags and 3 cups of sugar. If McKenzie uses 64 tea bags, how many cups of sugar w
cestrela7 [59]
So tis is a ratio  16 is to 3 or 16:3
if use 64 tea bags then how many cups of sugar so
turn 16:3 into fraction
16:3=16/3 or 3/16, it doesn't matter
then you want to find 64:x or 64/x or x/64

we know that 16/3=64/x because it tis an equivalent ratio
so 16/3=64/x
multiply both sdies by (3 times x)
16 times x times 3/3=64 times 3 times x/x
16 times x=64 times 3
16x=192
divide both sdies by 16
x=12
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5 0
3 years ago
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Amanda [17]
I believe that your answer is A.
4 0
3 years ago
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Simplify the following :
dlinn [17]

Answer:

1. 95/96

2. 27/7

3. -8/245

Explanation:

1. First add together the two fractions 3/4 + 5/6. Find the least common denominator. In this case we can use 12. The 3/4 changes to 9/12 and the 5/6 changes to 10/12. adding these together we get 19/12. Next we divide 8/5 by 19/12. We use the keep, change, flip method to change the divide to multiply. keep the first fraction, change divide into multiply, and then take the reciprocal of the second fraction. You will now do 5/8 x 19/12. We now get 95/96 (I made a mistake in the answers the first time because I was rushing)

2. Divide the 3/2 and the 8/9 first. I will use the KCF (keep, change, flip) method to divide. 3/2 x 9/8 = 27/16  Now we divide the 7/16. After using KCF we can simplify and cross cancel (simplfy after changing the fraction and signs) 27/16 x 16/7 --> 27/1 x 1/7   The answer will come out to be 27/7

3. since there are no parentheses divide first. Use KCF and after you get the answer multiply (it is the same using negative numbers just watch out for signs)

7 0
3 years ago
Factor. Explain.<br> 24x³y²-4x²y+84x^4
Elan Coil [88]

Answer:

\boxed{\bold{4x^2\left(6xy^2-y+21x^2\right)}}

Step By Step Explanation:

Apply Exponent Rule \bold{\:a^{b+c}=a^ba^c}

\bold{x^4=x^2x^2,\:x^3y^2=x^2x}

\bold{24x^2x-4x^2y+84x^2x^2}

Rewrite 84: \bold{21\cdot \:4}

Rewrite 24: \bold{6\cdot \:4}

\bold{6\cdot \:4x^2x-4x^2y+21\cdot \:4x^2x^2}

Factor Out Common Term \bold{4x^2}

\bold{4x^2\left(6xy^2-y+21x^2\right)}

➤ \boxed{\bold{Mordancy}}

6 0
2 years ago
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