So there's 5 body types each with 4 colors. 5x4 is 20. For each of these 20 cars there is 3 kinds of upholstery. 20x3 is 60. Therefore, the dealer would need a minimum of 60 cars to show his complete line. Hope this helped!
(1, 3.5 ) and (3, 3.5 )
the endpoints of the midsegment are at the midpoints of DE and DF
using the midpoint formula with D(0, 7), E(2, 0), F(6, 0)
midpoint of DE = [
(0 + 2),(7 + 0)] = (1, 3.5)
midpoint of DF = [(0 + 6),(7 + 0)] = (3, 3.5)
The correct answer is: 27 .
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Explanation:
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9^(3/2) = (√9)³ = 3³ = 3 * 3 * 3 = 27 .
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