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ANTONII [103]
3 years ago
14

Stuck on this question. May I please have some help?

Mathematics
2 answers:
Karolina [17]3 years ago
5 0

Answer:(-4,-3)

Step-by-step explanation:

Rina8888 [55]3 years ago
4 0

Answer:

So a point is (-3,-5) and the vertex is (-4,-3)

Step-by-step explanation:

This is in vertex form. Vertex form is y=a(x-h)^2+k where (h,k) is the vertex.

The vertex here is (-4,-3)... now just use a value of x to plug in (any value besides -4)

I will choice -3.  This gives -2(-3+4)^2-3

f(-3)=-2(1)^2-3

f(-3)=-2-3

f(-3)=-5

So a point is (-3,-5) and the vertex is (-4,-3)

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What is the value of t? <br> 2<br> 3<br> 6<br> 8
shepuryov [24]

Answer:

3

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
6 high school seniors choose from among 20 quotes for their yearbook. What is the probability that at least 2 of them choose the
shusha [124]

Using the binomial distribution, it is found that there is a 0.0328 = 3.28% probability that at least 2 of them choose the same quote.

<h3>What is the binomial distribution formula?</h3>

The formula is:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem, we have that:

  • There are 6 students, hence n = 6.
  • There are 20 quotes, hence the probability of each being chosen is p = 1/20 = 0.05.

The probability of one quote being chosen at least two times is given by:

P(X \geq 2) = 1 - P(X < 2)

In which:

P(X < 2) = P(X = 0) + P(X = 1).

Then:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{6,0}.(0.05)^{0}.(0.95)^{6} = 0.7351

P(X = 1) = C_{6,1}.(0.05)^{1}.(0.95)^{5} = 0.2321

Then:

P(X < 2) = P(X = 0) + P(X = 1) = 0.7351 + 0.2321 = 0.9672.

P(X \geq 2) = 1 - P(X < 2) = 1 - 0.9672 = 0.0328

0.0328 = 3.28% probability that at least 2 of them choose the same quote.

More can be learned about the binomial distribution at brainly.com/question/24863377

6 0
2 years ago
For the figure shown on the right, find the value of the variable and the measures of the angles. PLZ HELP
pychu [463]
P=69 degrees
Q=71 degrees
R=40 degrees

Explanation

All triangles equal up to 180 degrees.
First add all numbers without x.
Then add all xs.

5x+20=180
Subtract 20 from 180

5x=160
Divide 160 by 5

x=40

8 0
3 years ago
Type the correct answer in each box. Use numerals instead of words. Solve the equation by completing the square. x2 + 20x + 82 =
VikaD [51]
7=x^2+20x+82
0=x^2+20x+75

What adds to 20 and multiplies to 75? 5 and 15.

x^2+5x+15x+75
x(x+5) 15(x+5)
(x+15) (x+5)

Zeroes are x= -5 and x= -15
5 0
3 years ago
Una caja de 25 newtons se suspende mediante un cable con diámetro de 2cm¿cuál es el esfuerzo aplicado al cable?
Naddik [55]

El cable experimenta un esfuerzo axial de 79577.472 pascales por el peso de la caja.

<h3>¿Cómo calcular el esfuerzo aplicado sobre el cable?</h3>

La caja tiene masa y está sometida a un campo gravitacional, por tanto, tiene un peso (W), en newtons. Por el principio de acción y reacción (tercera ley de Newton), encontramos que el cable es tensionado debido a ese peso y su área transversal experimenta un esfuerzo axial (σ), en pascales.

Asumiendo una distribución uniforme de la fuerza sobre toda la superficie transversal de la cuerda, tenemos que el esfuerzo axial se calcula mediante la siguiente expresión:

σ = W / (π · D² / 4)

Donde:

  • W - Peso de la caja, en newtons.
  • D - Diámetro del área transversal de la caja, en metros.

Si sabemos que W = 25 N y D = 0.02 m, entonces el esfuerzo axial aplicado a la cuerda es:

σ = 25 N / [π · (0.02 m)² / 4]

σ ≈ 79577.472 Pa

<h3>Observación</h3>

La falta de problemas verificados en español sobre esfuerzos axiales obliga a buscar uno equivalente en inglés.

Para aprender más sobre esfuerzos axiales: brainly.com/question/13683145

#SPJ1

5 0
1 year ago
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