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TEA [102]
4 years ago
5

A. asymptote: B. Domain:

Mathematics
2 answers:
Arte-miy333 [17]4 years ago
8 0

Answer:

a

Step-by-step explanation:

tresset_1 [31]4 years ago
4 0
A is the answer I think
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△FSB∼△ZDR .
Leya [2.2K]

Answer:  22 units.

Step-by-step explanation:

Here FSB and ZDR are two triangles.

In which, FS = 38 unit, FB = 55 unit, ZD = 15.2 unit and ZR = x unit.

Also, \triangle FSB\sim \triangle ZDR

Thus, By the property of similarity,

\frac{FS}{ZD} = \frac{FB}{ZR}

⇒ \frac{38}{15.2} = \frac{55}{x}

⇒ x = \frac{55\times 15.2}{38}

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⇒ x = 22

Thus, ZR = 22 unit.

3 0
3 years ago
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Solve Q²= a(p²-b²)/p in form of y=mx+c
umka2103 [35]

Answer:

We want to rewrite:

q^2 = a*(p^2 - b^2)/p

as a linear equation, in the form:

y = m*x + c

So we start with:

q^2 = a*(p^2 - b^2)/p

we can expand the left side to get:

q^2 = (a/p)*p^2 - (a/p)*b^2

q^2 = a*p - (a/p)*b^2

Now we can ust define:

a*p = c

Then we can replace that to get:

q^2 = -(a/p)*b^2 + c

now we can replace:

q^2 = y

b^2 = x

Replacing these, we get:

y = -(a/p)*x + c

finally, we can replace:

-(a/p) = m

then we got the equation:

y = m*x + c

where:

y = q^2

x = b^2

c = a*p

m = -(a/p)

4 0
3 years ago
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