Using the z-distribution, as we are working with a proportion, it is found that 1016 constituents are required.
<h3>What is a confidence interval of proportions?</h3>
A confidence interval of proportions is given by:
In which:
is the sample proportion.
The margin of error is given by:
In this problem, we have a 95% confidence level, hence
, z is the value of Z that has a p-value of 
, so the critical value is z = 1.96.
The estimate is of 
, while the margin of error is of M = 0.03, hence solving for n we find the minimum sample size.
Rounding up, 1016 constituents are required.
More can be learned about the z-distribution at brainly.com/question/25890103
62.5%
What I did was divided 43.75 by 70 to get 0.625.
Then I moved the decimal over two places to the right to get 62.5.
Equation: w×0.6p
Explanation: 4.38 dollars for a 7.30 pound watermelon, you need to divide 4.38 by 7.3 to determine the price for each pound. 4.38÷7.3=0.60. W=the watermelons weight and P= watermelons price per pound.
What’s the question it’s not therer
