Answer:
A and B
Step-by-step explanation:

Now, look at your answer choices, which options are less than or equal to -2?
x ≤ -2, Check your answers:
A. -3 ≤ -2?
This statement is correct (-3 is < -2)
B. -2 ≤ -2 <== our original answer
This statement is correct (-2 is = to -2)
C. -1 ≤ -2
This statement is incorrect (-1 is > -2, not ≤ -2)
D. 0 ≤ -2
This statement is incorrect (0 is > -2, not ≤ -2)
E. 1 < -2
This statement is incorrect (1 is > -2, not ≤ -2)
Therefore, the correct options are A and B
Hope this helps!
Answer:
-2
Step-by-step explanation:
First, solve so that y is alone on its side of the equation by dividing both sides of the equation by 12.
12y=(-24)x
y=(-2)x
Therefore, the slope must be -2.
You have the formula already, just plug in 30 for s (speed) and solve for d (distance).
Answer:
- Both expressions should be evaluated with two different values. If for each substituted value, the final values of the expressions are the same, then the two expressions must be equivalent.
Step-by-step explanation:
<u>Given expressions</u>
- 4x - x + 5 = 3x + 5
- 8 - 3x - 3 = -3x + 5
Compared, we see the expressions are different as 3x and -3x have different coefficient
<u>Answer options</u>
Both expressions should be evaluated with one value. If the final values of the expressions are both positive, then the two expressions must be equivalent.
- Incorrect. Positive outcome doesn't mean equivalent
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Both expressions should be evaluated with one value. If the final values of the expressions are the same, then the two expressions must be equivalent.
- Incorrect. There are 2 values- variable and constant
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Both expressions should be evaluated with two different values. If for each substituted value, the final values of the expressions are positive, then the two expressions must be equivalent.
- Incorrect. Positive outcome doesn't mean equivalent.
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Both expressions should be evaluated with two different values. If for each substituted value, the final values of the expressions are the same, then the two expressions must be equivalent.