Answer:
x = infinite amount of solutions
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
Step-by-step explanation:
<u>Step 1: Define Equation</u>
8(2x + 5) = 16x + 40
<u>Step 2: Solve for </u><em><u>x</u></em>
- Distribute 8: 16x + 40 = 16x + 40
- Subtract 40 on both sides: 16x = 16x
- Divide 16 on both sides: x = x
Here we see that <em>x</em> does indeed equal <em>x</em>.
∴ <em>x</em> has an infinite amount of solutions.
b r = 178 + h;
b r + h = 676;
then, 178 + 2h = 676 => h = 498/2 = 249 => b r = 178 + 249 = 427
Answer:
676
Step-by-step explanation:
h=b+178=427
b=b=249
-------------
(b+178)+b=676
2b+178=676
2b=498
b=249
-------------
249+427=676
Kaneppeleqw and 2 more u
Answer:
The solve of that problem is that Hernry invested $18.000 in stocks and $6.000 in bonds.
Step-by-step explanation:
First, to explain you have to do a multiplication about 6 on three. Like three times more than bonds, the result is 18. Then you have to do a subtraction on $24.000 less $18.000, and the result is $6.000, so six is the amount on bonds. And is three times less than stocks, like the questions ask.
<span>y=2x+8 slope = 2
</span><span>parallel to y=2x+8, so equation has same slope = 2
</span><span>goes through point (−4,1)
</span>then
y = mx+b
1 = 2(-4) + b
b = 9
so the equation
y = 2x + 9
Answer:
<em>Scale factor=2</em>
<em>The perimeter of the enlarged figure is 19</em>
<em>The area of the enlarged figure is 4 times the area of the original figure</em>
Step-by-step explanation:
<u>Scaling</u>
There are two figures, the red rectangle (original) and the blue rectangle (enlarged).
To find the scale factor we directly compare the height of both rectangles and note:
height of original rectangle=1.5
height of enlarged rectangle=3
Thus, the scale factor is 3/1.5 = 2
Scale factor=2
The original perimeter is calculated as:
P1=2*1.5+2*3.25=3+6.5=9.5
The perimeter of the enlarged figure is 2 times the original perimeter
P2=2*9.5=19
The perimeter of the enlarged figure is 19
To calculate the area of the enlarged figure, we use
A2=H2*W2
Where H2 and W2 are the height and width of the enlarged figure.
Since
H2=2*H1
W2=2*W1
A2=4*A1
The area of the enlarged figure is 4 times the area of the original figure