All categories

3 years ago

Suppose f(x) = (5 – x)^3 and, g(x) = a + x^2, and f(g(x)) = (1 – x^2)^3. What is the value of a?

Mathematics

2 answers:

vodka [1.7K]3 years ago

7 0

Answer:

a=4

Step-by-step explanation:

that's the answer . ask me if u don't get it

Basile [38]3 years ago

6 0

I think it’s gonna be a=4

You might be interested in

Pls help i have a math question and I can`t figure out the answer

Svet_ta [14]

I can help! just let me know the question.

4 0

4 years ago

Explain how to use Pascal's Triangle to expand the binomial (3x-4y)^11

Mars2501 [29]

The solution to the binomial expression by using Pascal's triangle is:

$\mathbf{=177147x^{11}-2598156x^{10}y +17321040x^9y^2-69284160x^8y^3+184757760x^7y^4}$

$\mathbf{-344881152x^6y^5+459841536x^5y^6-437944320x^4y^7+291962880x^3y^8}$

$\mathbf{-129761280x2y^9+34603008xy^{10}-4194304y^{11}}$

<h3>How can we use Pascal's triangle to expand a binomial expression?</h3>

Pascal's triangle can be used to calculate the coefficients of the expansion of (a+b)ⁿ by taking the exponent (n) and adding the value of 1 to it. The coefficients will correspond with the line (n+1) of the triangle.

We can have the Pascal tree triangle expressed as follows:

1 1

1 2 1

1 3 3 1

1 4 6 4 1

--- --- --- --- --- --- --- --- --- --- --- --- --- --- ---

From the given information:

The expansion of (3x-4y)^11 will correspond to line 11.

Using the general formula for the Pascal triangle:

$\mathbf{(a+b)^n = c_oa^nb^0 + c_1 a^{n-1}b^1+c_{n-1}a^1b^{n-1}+c_na^0b^n}$

The solution to the expansion of the binomial (3x-4y)^11 can be computed as:

$\mathbf{=177147x^{11}-2598156x^{10}y +17321040x^9y^2-69284160x^8y^3+184757760x^7y^4}$

$\mathbf{-344881152x^6y^5+459841536x^5y^6-437944320x^4y^7+291962880x^3y^8}$

$\mathbf{-129761280x2y^9+34603008xy^{10}-4194304y^{11}}$

Learn more about Pascal's triangle here:

brainly.com/question/16978014

#SPJ1

5 0

2 years ago

y is directly proportional to x^3. it is known that =5 for a particular value of x. find the value of y when this value of y whe

alina1380 [7]

Answer:

The value of $y$ when the value of $x$ is multiplied by $\frac{1}{2}$ is $\frac{5}{8}$ .

Step-by-step explanation:

According to the statement, we have the following relationship:

$y = k\cdot x^{3}$ (1)

Where:

$x$ - Independent variable.

$y$ - Dependent variable.

$k$ - Proportionality constant.

We can eliminate the proportionality constant by constructing the following relationship:

$\frac{y_{2}}{y_{1}} = \left(\frac{x_{2}}{x_{1}} \right)^{3}$

If we know that $y_{1} = y$ , $y_{2} = 5$ , $x_{2} = x_{o}$ and $x_{1} = \frac{1}{2}\cdot x_{o}$ , then the value of $y$ when the value of $x$ is multiplied by $\frac{1}{2}$ is: