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GarryVolchara [31]
3 years ago
15

Suppose f(x) = (5 – x)^3 and, g(x) = a + x^2, and f(g(x)) = (1 – x^2)^3. What is the value of a?

Mathematics
2 answers:
vodka [1.7K]3 years ago
7 0

Answer:

a=4

Step-by-step explanation:

that's the answer . ask me if u don't get it

Basile [38]3 years ago
6 0
I think it’s gonna be a=4
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Round 9.42 to one decimal place
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The answer would be 9
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The scores on the GMAT entrance exam at an MBA program in the Central Valley of California are normally distributed with a mean
Kaylis [27]

Answer:

58.32% probability that a randomly selected application will report a GMAT score of less than 600

93.51%  probability that a sample of 50 randomly selected applications will report an average GMAT score of less than 600

98.38% probability that a sample of 100 randomly selected applications will report an average GMAT score of less than 600

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 591, \sigma = 42

What is the probability that a randomly selected application will report a GMAT score of less than 600?

This is the pvalue of Z when X = 600. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{600 - 591}{42}

Z = 0.21

Z = 0.21 has a pvalue of 0.5832

58.32% probability that a randomly selected application will report a GMAT score of less than 600

What is the probability that a sample of 50 randomly selected applications will report an average GMAT score of less than 600?

Now we have n = 50, s = \frac{42}{\sqrt{50}} = 5.94

This is the pvalue of Z when X = 600. So

Z = \frac{X - \mu}{s}

Z = \frac{600 - 591}{5.94}

Z = 1.515

Z = 1.515 has a pvalue of 0.9351

93.51%  probability that a sample of 50 randomly selected applications will report an average GMAT score of less than 600

What is the probability that a sample of 100 randomly selected applications will report an average GMAT score of less than 600?

Now we have n = 50, s = \frac{42}{\sqrt{100}} = 4.2

Z = \frac{X - \mu}{s}

Z = \frac{600 - 591}{4.2}

Z = 2.14

Z = 2.14 has a pvalue of 0.9838

98.38% probability that a sample of 100 randomly selected applications will report an average GMAT score of less than 600

8 0
3 years ago
Algebra 1 Prerequisites
frozen [14]
No solution

explanation:
5 0
3 years ago
Suppose that w and t vary inversely and that t = 5/12
Svetlanka [38]

Answer:

Option B. t=5/3w ;1/3

Step-by-step explanation:

We are told that w varies Inversely with t thus generally speaking w∝\frac{1}{t}  since they are inverted, <u>otherwise</u> if they were proportionally varied then w∝t. This means that there is a constant value ( a ) for which w is inversely proportional to t and can be mathematically expressed as:

w=\frac{a}{t}        Eqn. (1)

Now since we are given the values of w=4 and t=\frac{5}{12}, we can plug them in Eqn. (1) and find our constant of proportionality a as follow:

w=\frac{a}{t}\\ \\a=wt\\\\a=(4)(\frac{5}{12} )\\\\a=\frac{5}{3}

Now that we have our constant we can find the new t value for the second value of w=5 as follow:

w=\frac{a}{t} \\\\t=\frac{a}{w}\\ \\t=\frac{\frac{5}{3} }{5}\\\\t=\frac{5}{15}\\ \\t=\frac{1}{3}\\

Therefore based on the options give, we can see that Option B. is correct since

t=\frac{5}{3w} and for w=5, then t=\frac{1}{3}

8 0
3 years ago
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