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Bas_tet [7]
3 years ago
14

Will give Brainly What is the relationship between the sine and cosine of complementary angles in a right triangle? Please give

an example to support your answer.
Mathematics
1 answer:
Lina20 [59]3 years ago
4 0

Answer:

they are equal

Step-by-step explanation:

Consider the right triangle ABC with sides a, b, and c as shown in the figure.  

Let m(\angle A)=\alpha, and m(\angle B)=\beta.

\alpha +\beta=90^{\circ}, so angles A and B are complementary.

According to the definition of sine, and cosine:

\displaystyle{ \sin \alpha= \frac{opposite\ side}{hypotenuse} =\frac{a}{c} , and

\displaystyle{ \cos \beta= \frac{adjacent\ side}{hypotenuse} =\frac{a}{c}  

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Rita has a circular hot tub. the hot tub has a circumference of 25.12 feet. it is 3.5 feet deep.
natta225 [31]

Volume is a three-dimensional scalar quantity. The amount of water that the tub can hold is 4,981.75 litres.

<h3>What is volume?</h3>

A volume is a scalar number that expresses the amount of three-dimensional space enclosed by a closed surface.


Given the circumference of the tub is 25.12 feet, therefore, the radius of the circumference of the tub will be,

Circumference = 2πr

25.12 = 2×π×r

r = 3.9979ft ≈ 4ft

Now, the volume of the tub will be,

Volume = πr²h = π×(4²)×3.5 = 175.929 ft³

Since 1 ft³ is equal to 28.3168 litres, therefore, the amount of water that a tub can store is

Volume of water = 175 × 28.3168 = 4,981.75 litres

Hence, the amount of water that the tub can hold is 4,981.75 litres.

Learn more about Volume:

brainly.com/question/13338592

#SPJ1

7 0
3 years ago
Help me..............
Ira Lisetskai [31]
V = <span>πr^2h
so
r^2 = V/(</span><span>πh)
r = </span>√V/(πh)
r = √(Vπh) / πh

answer is D. last one
r = √(Vπh) / πh

7 0
3 years ago
Hurry i need answers ASAp
Neko [114]

Answer:

b

Step-by-step explanation:

6 0
3 years ago
A piece of wire 23 m long is cut into two pieces. One piece is bent into a square and the other is bent into an equilateral tria
AURORKA [14]

Answer:

For maximum area, all of the wire should be used to construct the square.

The minimum total area is obtained when length of the wire is 10m

Step-by-step explanation:

For maximum,  we use the whole length

For minimum,

supposed the x length was used for the square,

the length of the side of the square = x/4m

Area = \frac{x^{2} }{16}

For the equilateral triangle, the length of the side =  \frac{23 - x}{3}

Area = \frac{\sqrt{3} }{4}  a^{2}  = \frac{\sqrt{3} }{4} (\frac{23 - x}{3} )^{2}

Total Area = \frac{x^{2} }{16}  + \frac{\sqrt{3} }{36} (23-x)^{2}

\frac{dA}{dx}  = \frac{x}{8}  -  \frac{\sqrt{3} }{18} (23 - x)\\

\frac{d^{2}A }{dx^{2} }  = \frac{1}{8}  + \frac{\sqrt{3} }{18}  > 0, therefore it is minimum

\frac{dA}{dx}  = 0 \\\\

\frac{x}{8}  -  \frac{\sqrt{3} }{18} (23 - x) = 0\\

x = 10.00m

3 0
3 years ago
Read 2 more answers
-4f, when f = 2<br><br><br><br><br><br><br> Cbnxcnncncncjfjfjdjffj
jekas [21]

Answer:

the answer is negative 8. just plug f in

5 0
4 years ago
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