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joja [24]
3 years ago
15

How many different ways could a baking contest be judged if 15 pies are entered and 4 ribbons are awarded?

Mathematics
2 answers:
Rashid [163]3 years ago
8 0
This is a question of combination since it does not take into account the order of the pies. The answer would be 1365. There are 1365 ways a baking contest ways can be judged if 4 ribbons are awarded with 15 pie entries. 

In case you need the order, then the permutation answer would be 32760.
RoseWind [281]3 years ago
7 0

Answer:

1365

Step-by-step explanation:

We are given that 15 pies are entered in the contest.

Out of 15 , 4 are awarded with ribbons.

Now we are supposed to find How many different ways could a baking contest be judged.

Since the order of pie doesn't matter over here.

So, we will use combination.

^nC_r=\frac{n!}{r!(n-r)!}

Substitute n = 15

r = 4

So, ^{15}C_4=\frac{15!}{4!(15-4)!}

^{15}C_4=\frac{15!}{4!(11)!}

^{15}C_4=\frac{15 \times 14\times 13 \times 12 \times 11!}{4!(11)!}

^{15}C_4=\frac{15\times 14\times 13 \times 12}{4\times 3 \times 2\times 1}

^{15}C_4=1365

Hence there are 1365 ways in which a baking contest could be judged.

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_______________________________________________________
<u>
Note</u>:
 The formula/equation for the area, "A" , of a triangle is:

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 in which:   "A = area of the triangle" ; 
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{Note:  Let us assume that the given area was "12.25 cm² " .}. 
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