Answer:
7/25
Step-by-step explanation:
θ lies in quadrant ii
so 2θ lies in quadrant iv
csc θ=5/3
sin θ=3/5 (sin θ=1/csc θ)
[cos(α+β)=cosαcosβ-sinαsinβ]
cos (2θ)=cos(θ+θ)=cos θ cos θ-sin θ sin θ=cos² θ-sin ²θ=1-sin²θ-sin²θ=1-2sin²θ
=1-2 (3/5)²
=1-2(9/25)
=1-18/25
=(25-18)/25
=7/25
Answer:
Given: Diameter of cone = 38 feet and height of cone = 14 feet.
Volume of cone V with radius r is one-third the area of the base B times the height h.
i,e
=
......[1]
,where B = 
First find the radius(r);
Using Diameter(D) = 2r
38 =2r
Divide both side by 2 we get;

Simplify:
19 = r
or r =19 feet
Now, substitute the value of r = 19 feet and h = 14 feet in [1] [ Use value of
]
then, we have:

or
V = 
or
V =
≈ 5,294.67 cubic feet.
therefore, the volume of pile is; ≈ 5,294.67 cubic feet.
Answer:
Find the distance between (2,3) (4, -7)
= 6
Find the distance between (-9,-4) (-3,6)
= -10
ANSWER
To graph the function
we need to plot some few points within one period. Since the interval is not given, we shall use
'
.
We plot the above points to obtain the graph as shown in the attachment.
Aas is not d triangle buddy