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katrin2010 [14]
3 years ago
7

What does 5x-2=6+x equal to

Mathematics
2 answers:
Dmitrij [34]3 years ago
8 0
The Answer would be 2
zheka24 [161]3 years ago
4 0

Answer: 2

Step-by-step explanation:

honestly just get mathpapa for math , its so easy

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Sam does 11 jumping jacks in 8 seconds. If he does the jumping jacks at a constant rate, how many jumping jacks can he do in 20
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Answer:

baila como juana la cubana

Step-by-step explanation:

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3 years ago
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HELP!! Algebra help!! Will give stars thank u so much <333
Anna35 [415]

Answers:

  • Part a)  \bf{\sqrt{x^2+(x^2-3)^2}
  • Part b)  3
  • Part c)   2.24
  • Part d)  1.58

============================================================

Work Shown:

Part (a)

The origin is the point (0,0) which we'll make the first point, so let (x1,y1) = (0,0)

The other point is of the form (x,y) where y = x^2-3. So the point can be stated as (x2,y2) = (x,y). We'll replace y with x^2-3

We apply the distance formula to say...

d = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\\\\d = \sqrt{(0-x)^2+(0-y)^2}\\\\d = \sqrt{(0-x)^2+(-y)^2}\\\\d = \sqrt{x^2 + y^2}\\\\d = \sqrt{x^2 + (x^2-3)^2}\\\\

We could expand things out and combine like terms, but that's just extra unneeded work in my opinion.

Saying d = \sqrt{x^2 + (x^2-3)^2} is the same as writing d = sqrt(x^2-(x^2-3)^2)

-------------------------------------------

Part (b)

Plug in x = 0 and you should find the following

d(x) = \sqrt{x^2 + (x^2-3)^2}\\\\d(0) = \sqrt{0^2 + (0^2-3)^2}\\\\d(0) = \sqrt{(-3)^2}\\\\d(0) = \sqrt{9}\\\\d(0) = 3\\\\

This says that the point (x,y) = (0,3) is 3 units away from the origin (0,0).

-------------------------------------------

Part (c)

Repeat for x = 1

d(x) = \sqrt{x^2 + (x^2-3)^2}\\\\d(1) = \sqrt{1^2 + (1^2-3)^2}\\\\d(1) = \sqrt{1 + (1-3)^2}\\\\d(1) = \sqrt{1 + (-2)^2}\\\\d(1) = \sqrt{1 + 4}\\\\d(1) = \sqrt{5}\\\\d(1) \approx 2.23606797749979\\\\d(1) \approx 2.24\\\\

-------------------------------------------

Part (d)

Graph the d(x) function found back in part (a)

Use the minimum function on your graphing calculator to find the lowest point such that x > 0.

See the diagram below. I used GeoGebra to make the graph. Desmos probably has a similar feature (but I'm not entirely sure). If you have a TI83 or TI84, then your calculator has the minimum function feature.

The red point of this diagram is what we're after. That point is approximately (1.58, 1.66)

This means the smallest d can get is d = 1.66 and it happens when x = 1.58 approximately.

6 0
3 years ago
I need help please! I've been stuck on this for a week and its really stressful lol
worty [1.4K]

Answer:

y=0.2*4^{x}

Step-by-step explanation:

Notice when x increases 1, y is 4 times the previous one, so

the function is like y=C*4^{x}

To determine the constant C, put any pair of (x, y)

Use x = 0, y = 0.2, so

0.2 = C*4^{0} = C * 1 = C

then y=0.2*4^{x}

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Explanation:
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Last year 500 people attended a concert this year 900 people attended what was the percent increase in attendance from last year
IRISSAK [1]

Answer:

80

Step-by-step explanation:

500 to 900? = 80.

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