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3 years ago

Drag each tile to the correct box. Not all tiles will be used.

Mathematics

1 answer:

german3 years ago

4 0

Answer:

P=$880,I=$92.40

P=$675,I=$94.50

P=$770,I=$96.79

Step-by-step explanation:

Simple interest rate is the interest eared on principal amount only over time:

$I=PRT$

#$880 at 5.25% for 2 years

$I=PRT, P=880, R=0.0525, T=2\\\\=880\times 0.0525\times 2\\\\=92.4$

Hence, the interest earned is $92.40

#$675 at 3.5% for 4 years:

$I=PRT, P=675, R=0.035, T=4\\\\=675\times 0.035\times 4\\\\=94.5$

Hence, the interest earned is $94.50

#$770 at 4.19 for 3 years:

$I=PRT, P=770, R=0.0419, T=3\\\\=770\times 0.0419\times 3\\\\=96.79$

Hence, the interest earned is $96.79

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What is the interest rate for a investment of $6000 for a rate of 3% and a interest of $450

LiRa [457]

6000 * .03 = 180 450+ 180= 630 Hope this helps

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4 years ago

Is throw right ASAP

Alexxx [7]

Answer: No it is not.

Step-by-step explanation:

All linear functions can be written in the form y = mx + b, where m is the slope and b is the y-intercept (slope-intercept form). Alternatively, a linear function can be expressed in the form y – y0 = m(x – x0), where m is the slope and (x0, y0) is a point on the line (point-slope form).

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3 years ago

Read 2 more answers

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Nat2105 [25]

Answer:

1) Zero based on (-16·t - 2) is t = -1/8 second

2) Zero based on (t - 1) is t = 1 second

Step-by-step explanation:

The given functions representing the height of the beach ball the child throws as a function of time are;

y = (-16·t - 2)·(t - 1) and y = -16·t² + 14·t + 2

We note that (-16·t - 2)·(t - 1) = -16·t² + 14·t + 2

Therefore, the function representing the height of the beachball, 'y', is y = (-16·t - 2)·(t - 1) = -16·t² + 14·t + 2

The zeros of a function are the values of the variables, 'x', of the function that makes the value of the function, f(x), equal to zero

In the function of the question, we have;

y = (-16·t - 2)·(t - 1) = -16·t² + 14·t + 2

The above equation can be written as follows;

y = (-16·t - 2) × (t - 1)

Therefore, 'y' equals zero when either (-16·t - 2) = 0 or (t - 1) = 0

1) The zero based on (-16·t - 2) = 0, is given as follows;

(-16·t - 2) = 0

∴ t = 2/(-16) = -1/8

t = -1/8 second

The zero based on (-16·t - 2) is t = -1/8 second

2) The zero based on (t - 1) = 0, is given as follows;

(t - 1) = 0

∴ t = 1 second

The zero based on (t - 1) is t = 1 second

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3 years ago

ASAP 7 POINTS + LINK TO A 50 POINT QUESTION

Tresset [83]

Answer: 2: an equation in the form y = mx + b

1. An x/y table may have two entries with the same x; not a function in that case.

2. That's a line with a slope; for each x there's a single y, definitely a function

3. Ordered pairs -- like the table, the same x with different ys is possible, which wouldn't be a function.

4. List of numbers -- a list isn't a function, at least not without more context

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3 years ago

Please help and Imma be postin these all night I literally suck at algebra two so just check my profile if your good at math :)

Simora [160]

Answer:

The range of the equation is y ≥ 9 ⇒ C

Step-by-step explanation:

The quadratic equation y = ax² + bx + c, represents by a parabola of vertex (h, k), where h = $\frac{-b}{2a}$ and k is the value of y at x = h

The range of the quadratic if it has a minimum vertex is y ≥ k, and y ≤ k if it has a maximum vertex

The parabola has a minimum vertex if the value of a is positive and a maximum vertex if the value of a is negative

∵ The equation is y = x² + 9

→ Compare it with the form above to find a and b

∴ a = 1 and b = 0

∵ a is a positive number

∴ The parabola has a minimum vertex

→ By using the 1st rule above

∴ The range is y ≥ k

→ Use the rule of h above to find it

∵ h = $\frac{-(0)}{2(1)}$ = $\frac{0}{2}$

∴ h = 0

→ To find k substitute x by the value of h and y by k

∵ k = (0)² + 9

∴ k = 0 + 9

∴ k = 9

∴ The range of the equation is y ≥ 9

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3 years ago