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katen-ka-za [31]
3 years ago
15

The ratio of boys to girls is 5:7. If there are 48 students in a school play, how many more girls than boys are in the play?

Mathematics
1 answer:
olganol [36]3 years ago
4 0

Answer:

There are 13 more girls than boys

Step-by-step explanation:

5×7=35

48-35=13

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You invest $2,500 in an account that grows 5% each year. what will be your investment amount after 6 years?
lesantik [10]

Answer:  b. $3,374.65

Step-by-step explanation:

The exponential equation of growth (continuously) is given by :-

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Given : You invest $2,500 in an account that grows 5% each year.

i.e.  A= $2,500  and r= 5%=0.05

Then, the equation model this situation will be :-

y=2500e^{0.05x}=2500(1.05)^x

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y=2500e^{0.05\times6}\\\\\Rightarrow\ y=2500e^{0.3}=3374.64701894\approx3374.65

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4 0
3 years ago
20% of what number is 75?
nataly862011 [7]

Answer:

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Step-by-step explanation:

7 0
3 years ago
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Derivatives concept:<br> Exercises using the definition of derivatives:<br><br> (Full development)
krok68 [10]

(A) <em>f(x)</em> = 7 is constant, so <em>f(x</em> + <em>h)</em> = 7, too, which makes <em>f(x</em> + <em>h)</em> - <em>f(x)</em> = 0. So <em>f'(x)</em> = 0.

(B) <em>f(x)</em> = 5<em>x</em> + 1   ==>   <em>f(x</em> + <em>h)</em> = 5 (<em>x</em> + <em>h</em>) + 1 = 5<em>x</em> + 5<em>h</em> + 1

==>   <em>f(x</em> + <em>h)</em> - <em>f(x)</em> = 5<em>h</em>

Then

\displaystyle f'(x) = \lim_{h\to0}\frac{5h}h = \lim_{h\to0}5 = 5

(C) <em>f(x)</em> = <em>x</em> ² + 3   ==>   <em>f(x</em> + <em>h)</em> = (<em>x</em> + <em>h</em>)² + 3 = <em>x</em> ² + 2<em>xh</em> + <em>h</em> ² + 3

==>   <em>f(x</em> + <em>h)</em> - <em>f(x)</em> = 2<em>xh</em> + <em>h</em> ²

\implies\displaystyle f'(x) = \lim_{h\to0}\frac{2xh+h^2}h = \lim_{h\to0}(2x+h) = 2x

(D) <em>f(x)</em> = <em>x</em> ² +<em> </em>4<em>x</em> - 1   ==>   <em>f(x</em> + <em>h)</em> = (<em>x</em> + <em>h</em>)² + 4 (<em>x</em> + <em>h</em>) - 1 = <em>x</em> ² + 2<em>xh</em> + <em>h</em> ² + 4<em>x</em> + 4<em>h</em> - 1

==>   <em>f(x</em> + <em>h)</em> - <em>f(x)</em> = 2<em>xh</em> + <em>h</em> ² + 4<em>h</em>

\implies \displaystyle f'(x) = \lim_{h\to0}\frac{2xh+h^2+4h}h = \lim_{h\to0}(2x+h+4) = 2x+4

5 0
3 years ago
216^-1.5t+15=1<br> please solve and give the correct answers<br> will give brainlest
LekaFEV [45]
If +15 is also a a part of the power of 216 there will be no solution:
216^(-1.5t)=1-15
216^(-1.5t)=-14
-1.5t= 216 base log -14 as log with negative value(-14 in this problem) has no solution so,
I guess it is 216^(-1.5t+15)=1 right?

216^-1.5t+15=1
-1.5t+15=216 base log 1
-1.5t+15=0(Any log with value 1 of anybase has no value which is peopwely 0)
-1.5t=-15
t=15/1.5
t=10
3 0
4 years ago
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