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mrs_skeptik [129]
3 years ago
5

Solve the simultaneous equations.3x-y=1, 2x + 5y = 41​

Mathematics
1 answer:
inessss [21]3 years ago
3 0
Y=3x-1, Y=-2/5x + 41/5
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Find the distance between the pair of points.
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Answer:

Distance is \sqrt{290} units

Step-by-step explanation:

Use the distance formula which is d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} where d is the distance between points (x_1,y_1) and (x_2,y_2)

We are given that (x_1,y_1) is (-6,-23) and (x_2,y_2) is (-23,-24), therefore the distance between the two points is:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

d=\sqrt{(-23-(-6))^2+(-24-(-23))^2}

d=\sqrt{(-23+6))^2+(-24+23))^2}

d=\sqrt{(-17)^2+(-1)^2}

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Therefore, the distance between (-6,-23) and (-23,-24) is \sqrt{290} units.

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3 years ago
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3^-2 is simply 1/9.

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<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>2</em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>2</em><em> </em><em> </em><em>3</em><em> </em><em> </em><em>4</em><em> </em><em> </em><em>2</em><em> </em><em> </em><em>5</em><em> </em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>3</em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>1.</em><em> </em><em>3.</em><em> </em><em>2.</em><em> </em><em>1.</em><em> </em><em>5</em>

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