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Monica [59]
3 years ago
7

Monica walks every day for exercise at a rate of 1 km every 20 minutes at this rate how many meters can Monica walk in one hour

explain how you found your answer and please write neatly where I can understand it please and it is due by tomorrow please help me????!!!!
Mathematics
2 answers:
Ierofanga [76]3 years ago
7 0
Let's turn 1km/20 min into a ratio so it is easier to look at
1 km : 20 min
3 km : 60 min

In an hour there are 60 min and there are three 20 min in an hour (60/20=3), so we also multiply the km by 3.

In one hour she can walk 3 km, but we need to convert that into meters.
1 km = 1000 m
3 km = 3000 m

To convert 1 km to 3 km, we must multiply that by 3. That means we must multiply the 1000 m side too so that the ratio is equal. 

Therefore, she can walk 3000 m in one hour. 


olga nikolaevna [1]3 years ago
5 0
There are three 20 minutes in an hour so she can travel 3 km in an hour
1 km = 1000m so 3km = 3000m she can walk 3000m in an hour
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myrzilka [38]
<h3>Answer:   15x^(7/3) - 8x^(7/4) + x + 9000</h3>

=========================================================

Explanation:

If you know the cost function C(x), to find the marginal cost, we apply the derivative.

Marginal cost = derivative of cost function

Marginal cost = C ' (x)

Since we're given the marginal cost, we'll apply the antiderivative (aka integral) to figure out what C(x) is. This reverses the process described above.

\text{Cost} = \text{antiderivative of marginal cost}\\\\\displaystyle C(x) = \int \left(35x^{4/3} - 14x^{3/4} + 1\right)dx\\\\

C(x) = \frac{1}{1+4/3}*35x^{4/3+1} - \frac{1}{1+3/4}*14x^{3/4+1} + x + D\\\\C(x) = \frac{1}{7/3}*35x^{7/3} - \frac{1}{7/4}*14x^{7/4} + x + D\\\\C(x) = \frac{3}{7}*35x^{7/3} - \frac{4}{7}*14x^{7/4} + x + D\\\\C(x) = 15x^{7/3} - 8x^{7/4} + x + D\\\\

D represents a fixed constant. I would have used C as the constant of integration, but it's already taken by the cost function C(x).

To determine the value of D, we plug in x = 0 and C(x) = 9000. This is because we're told the fixed costs are $9000. This means that when x = 0 units are made, you still have $9000 in costs to pay. This is the initial value. You'll find that all of this leads to D = 9000 because everything else zeros out.

Therefore, we go from this

C(x) = 15x^{7/3} - 8x^{7/4} + x + D\\\\

to this

C(x) = 15x^{7/3} - 8x^{7/4} + x + 9000\\\\

which is the final answer.

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erma4kov [3.2K]

Answer:

It is B.

Step-by-step explanation:

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