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Fed [463]
3 years ago
6

5ac+10ab-2c^2-4bc Factor.

Mathematics
1 answer:
babymother [125]3 years ago
7 0
(5ac+10ab)+(-2c^2-4bc)

5a(c+2b) -2c(c+2b)


(5a-2c) (c+2b)
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Each equation below is followed by several stories.
zloy xaker [14]
Not sure sorry edit : oh sorry I was suppose to add this in the comment section
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3 years ago
David owns a food truck that sells tacos and burritos. He sells each taco for $4.50 and each burrito for $7.75. Yesterday David
inna [77]
7.75+4.50
Then this equals 12.25 ; You gone want to divide this

519.25 \ 12.25 you get $42.38 or $42.39 if you round.

Or 4.50 x 60 is $270
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3 0
3 years ago
Ashley and her sister decide to split the cost of dinner , which is $14 . How much will each sister pay?
Mazyrski [523]

Answer:

14÷2=7

7 is your answer. hope this helps

5 0
2 years ago
Read 2 more answers
The equation's X-y= 2, -2y=-2, X+ y = 2, and x+2y=-2 are shown on the graph below.
ziro4ka [17]

Answer:

A.) x-y=2 and x+2y=-2

Step-by-step explanation:

For option A, we have:

x-y=2

x+2y=-2

Subtract the first equation from the second, to get:

2y--y=-2-2

This implies that:

2y+y=-2-2

Simplify to get:

3y=-4

Divide both sides by 3 to get:

y =  -  \frac{4}{3}  =  - 1.3

We substitute y=-1.3 into the first equation to get:

x--1.3=2

x+1.3=2

x=2-1.3

x=0.7

The solution is (0.7,-1.3), which is approximately (0.7, -1.4)

By inspection, all the other factors have solutions not close to (0.7, -1.4)

3 0
3 years ago
Read 2 more answers
2. In a given population of two-earner male-female couples, male earnings have a mean of $40,000 per year and a standard deviati
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Answer: $85,000

Step-by-step explanation:

Given : In a given population of two-earner male-female couples, male earnings have a mean of $40,000 per year and a standard deviation of $12,000.

\mu_M=40,000\ \ ;\sigma_M=12,000

Female earnings have a mean of $45,000 per year and a standard deviation of $18,000.

\mu_F=45,000\ \ ;\sigma_F=18,000

If  C denote the combined earnings for a randomly selected couple.

Then, the mean of C will be :-

\mu_c=\mu_M+\mu_F\\\\=40,000+45,000=85,000

Hence, the mean of C = $85,000

8 0
3 years ago
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