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3 years ago

What is the solution to the following equation x²+3x+7=0

Mathematics

2 answers:

katrin [286]3 years ago

8 0

Answer:

x =(3-√37)/2=-1.541

x =(3+√37)/2= 4.541

Step-by-step explanation:

to long to explain sorry but trust me

Papessa [141]3 years ago

4 0

Answer:

The answer to your question is below

Step-by-step explanation:

Data

Equation x² + 3x + 7 = 0

Let's solve this equation by two methods.

1) Completing the perfect square trinomial

x² + 3x = -7

x² + 3x + (3/2)² = -7 + (3/2)²

(x + 3/2)² = -7 + 9/4

(x + 3/2)² = -19/4

x + 3/2 = √-19/√4

x = -3/2 + √-19/2 It has imaginary solutions.

2.- Graph the equation

See the graph below.

In the graph we notice that the equation does not cross the x-axis so it does not have real solution.

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3 years ago

Which expression is equivalent to (r Superscript negative 7 Baseline) Superscript 6? r Superscript 42 StartFraction 1 Over r Sup

vodomira [7]

Power rule of exponents says that the power of the power of a exponent is equal to the multiplying both the powers. The expression which is equal to the given expression is,

$\dfrac{1}{(r)^{42}}$

The option B is the correct option.

Given information-

The given expression in the problem is,

$[(r)^{-7}]^5$

<h3>Power rule of exponents</h3>

Power rule of exponents says that the power of the power of a exponent is equal to the multiplying both the powers.

Suppose<em> </em><em>x</em> is a number with power <em>a. </em>The power is power of the power of number <em>x. </em>Then by the power rule of the exponents,

$(x^a)^b=x^{ab}$

Using the power rule of the exponents given expression can be written as,

$[(r)^{-7}]^6=(r)^{-7\times 6} 
$

$[(r)^{-7}]^6=(r)^{-42}$

<h3>Negative exponents rule</h3>

Negative exponents rule says that when a power of a number is negative, then write the number in the denominator with the same power with positive sign.Thus,

$[(r)^{-7}]^6=\dfrac{1}{(r)^{42}}$