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Alisiya [41]
3 years ago
15

Please help!! Thank you

Mathematics
2 answers:
Nikitich [7]3 years ago
6 0
A.

D. Is wrong
Hope this helps
faust18 [17]3 years ago
3 0
D , I hope this helps
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Four batsmen on a cricket team had a mean of 42.5 runs the other 7 batsmen had a mea of 18 what was the mean number of scored by
Ira Lisetskai [31]

Answer:

The mean score of the entire team is 26.909.

Step-by-step explanation:

Given that four batsmen had a mean of 42.5.

Let $ \textbf{B}_{\textbf{i} $, where $ i = 1, 2, 3, \hdots, 11 $ denote the batsmen.

From the first statement, we have:

$ \frac{B_1 + B_2 + B_3 + B_4}{4} = 42.5 $

$ \implies B_1 + B_2 + B_3 + B_4 = 42.5 \times 4 =  \textbf{170} $

Therefore, the sum of the scores of the first four batsmen is 170.

Now, from the second statement we have:

$ \frac{B_5 + B_6 + B_7 + B_8 + B_9 + B_{10} + B_{11}}{7} = 18 $

$ \implies B_5 + B_6 + B_7 + B_8 + B_9 + B_{10} + B_{11} = 18 \times 7 = \textbf{126} $

That is, the sum of the scores of the remaining 7 batsmen is 126.

Now, to calculate the average(mean) of the entire team, we add the individual scores and divide it by 11.

$ \implies \frac{B_1 + B_2 + B_3 + B_4 + B_5 + B_6 + B_7 + B_8 + B_9 + B_{10} + B_{11}}{11} = \frac{170 + 126}{11} $

$ = \frac{296}{11} $

$ = \textbf{26.90} $ which is the required answer.

8 0
3 years ago
What is the mode of the following numbers? 6,4,1,9,3,8,3,5,10
siniylev [52]

Answer:

Step-by-step explanation:

Mode is the number that appears most often in a set, so for this one the mode would be 3 since it appears the most often

7 0
3 years ago
What is the square footage of a triangle
jenyasd209 [6]
Multiply the base by the height and then divide it by 2.
7 0
3 years ago
Write a polynomial of degree 5 with zero x=0,i square root 7, -2i
professor190 [17]

Answer:

P(x)=x^5+11x^3+28x

Step-by-step explanation:

<u>Roots of a polynomial</u>

If we know the roots of a polynomial, say x1,x2,x3,...,xn, we can construct the polynomial using the formula

P(x)=a(x-x_1)(x-x_2)(x-x_3)...(x-x_n)

Where a is an arbitrary constant.

We know three of the roots of the degree-5 polynomial are:

x_1=0;\ x_2=\sqrt{7}\boldsymbol{i}:\ x_3=-2\boldsymbol{i}

We can complete the two remaining roots by knowing the complex roots in a polynomial with real coefficients, always come paired with their conjugates. This means that the fourth and fifth roots are:

x_4=-\sqrt{7}\boldsymbol{i}:\ x_3=+2\boldsymbol{i}

Let's build up the polynomial, assuming a=1:

P(x)=(x-0)(x-\sqrt{7}\boldsymbol{i})(x+\sqrt{7}\boldsymbol{i})(x-2\boldsymbol{i})(x+2\boldsymbol{i})

Since:

(a+b\boldsymbol{i})\cdot (a-b\boldsymbol{i})=a^2+b^2

P(x)=(x)(x^2+7)(x^2+4)

Operating the last two factors:

P(x)=(x)(x^4+11x^2+28)

Operating, we have the required polynomial:

\boxed{P(x)=x^5+11x^3+28x}

7 0
3 years ago
Which is NOT equivalent to 64? A) 26 B) (24 )(4) C) (23 )(42 ) D) 43
Vadim26 [7]
Only B is equivalent to 64

26 ≠ 64
24 x 4 is 64 = 64 
23 x 42 is 966≠ 64
43≠64

hope this helps
3 0
3 years ago
Read 2 more answers
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