Answer:
1 rubber cube dude give since we'll
Answer:
= 5x -10
Step-by-step explanation:
=(3)(3x)+(3)(−4)+(−2)(2x)+(−2)(−1)
=9x+−12+−4x+2
Combine Like Terms:
=9x+−12+−4x+2
=(9x+−4x)+(−12+2)
=5x+−10
9514 1404 393
Answer:
a) E = 6500 -50d
b) 5000 kWh
c) the excess will last only 130 days, not enough for 5 months
Step-by-step explanation:
<u>Given</u>:
starting excess (E): 6500 kWh
usage: 50 kWh/day (d)
<u>Find</u>:
a) E(d)
b) E(30)
c) E(150)
<u>Solution</u>:
a) The exces is linearly decreasing with the number of days, so we have ...
E(d) = 6500 -50d
__
b) After 30 days, the excess remaining is ...
E(30) = 6500 -50(30) = 5000 . . . . kWh after 30 days
__
c) After 150 days, the excess remaining would be ...
E(150) = 6500 -50(150) = 6500 -7500 = -1000 . . . . 150 days is beyond the capacity of the system
The supply is not enough to last for 5 months.
We're going to assume that x = # of days.
Plug 12 in as x:
4 × 12 = 48
48 + 6 = 54
They produced 54 boats in 12 days.
37/50 as a decimal is: <span>0.74
</span><span>To get 37/50 converted to decimal, you simply divide 37 by 50.
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