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3 years ago

Solve 4(x - 3) - 2(x - 1) > 0. {x | x > 2} {x | x > 5} {x | x > 7} {x | x > 14}

Mathematics

2 answers:

MatroZZZ [7]3 years ago

4 0

X>5 is the answer!!!

postnew [5]3 years ago

3 0

Answer:

{x | x > 5}

Step-by-step explanation:

if u dont know how to figure this out, i suggest u ask ur teacher to explain it

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You earn $28 for washing 4 cars. How much do you earn for washing 3 cars?

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Step-by-step explanation:

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3 years ago

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Find the missing side length using the Pythagorean Theorem. a²+6² = c²

r-ruslan [8.4K]

Answer:

Step-by-step explanation:

Hello!

In the Pythagorean theorem, the summation of the square of the legs in a right triangle is equal to the square of the hypotenuse.

Let a and b be the legs, and c is the hypotenuse.

a² + b² = c²

In this equation, the hypotenuse is 30, and the measure of one leg is 24.

We can solve this by plugging in the values.

a² + b² = c²
24² + b² = 30²
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3 years ago

(1/1+sintheta)=sec^2theta-secthetatantheta pls help me verify this

Xelga [282]

Answer:

See Below.

Step-by-step explanation:

We want to verify the equation:

$\displaystyle \frac{1}{1+\sin\theta} = \sec^2\theta - \sec\theta \tan\theta$

To start, we can multiply the fraction by (1 - sin(θ)). This yields:

$\displaystyle \frac{1}{1+\sin\theta}\left(\frac{1-\sin\theta}{1-\sin\theta}\right) = \sec^2\theta - \sec\theta \tan\theta$

Simplify. The denominator uses the difference of two squares pattern:

$\displaystyle \frac{1-\sin\theta}{\underbrace{1-\sin^2\theta}_{(a+b)(a-b)=a^2-b^2}} = \sec^2\theta - \sec\theta \tan\theta$

Recall that sin²(θ) + cos²(θ) = 1. Hence, cos²(θ) = 1 - sin²(θ). Substitute:

$\displaystyle \displaystyle \frac{1-\sin\theta}{\cos^2\theta} = \sec^2\theta - \sec\theta \tan\theta$

Split into two separate fractions:

$\displaystyle \frac{1}{\cos^2\theta} -\frac{\sin\theta}{\cos^2\theta} = \sec^2\theta - \sec\theta\tan\theta$

Rewrite the two fractions:

$\displaystyle \left(\frac{1}{\cos\theta}\right)^2-\frac{\sin\theta}{\cos\theta}\cdot \frac{1}{\cos\theta}=\sec^2\theta - \sec\theta \tan\theta$

By definition, 1 / cos(θ) = sec(θ) and sin(θ)/cos(θ) = tan(θ). Hence:

$\displaystyle \sec^2\theta - \sec\theta\tan\theta \stackrel{\checkmark}{=} \sec^2\theta - \sec\theta\tan\theta$

Hence verified.

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3 years ago

Find the circumference of the circle and show work

expeople1 [14]

Answer:

$\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}$

Circumference of a circle is given by

$C = 2\pi \: r$

Given - Diameter of circle = 10 yards

$radius = \frac{diameter}{2} = \frac{10}{2} \\ \\ \implies \: 5 \: yards$

now ,

substituting the value of r in the formula of circumference ~

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2 years ago

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svetlana [45]

24.7/100 yer welcome

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