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Dovator [93]
3 years ago
13

X^2- 4x- 6y- 14=0 in standard parabola form.

Mathematics
1 answer:
uranmaximum [27]3 years ago
7 0
<span>X^2- 4x- 6y- 14=0
6y = x^2 - 4x - 14 
Divide through by 6:-

y = (1/6)x^2 - (2/3)x -  7/3</span>
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