Answer:
Yes. No graph paper.
Step-by-step explanation:
Let's say the 3 points are A, B, C.
If A, B and C lie on one line then 

Hence, they lie on one line.
You don't need to use a graph paper to prove it.
F(X)= x+1/4x-2
f(2) = (2 + 1)/[(4)(2) - 2]
f(2) = 3/6 = 1/2
In circle O, RT and SU are diameters. mArc R V = mArc V U = 64°. Thus, option C is correct.
Given that:
mArc R V = mArc V U,
Angle S O R = 13 x degrees
Angle T O U = 15 x - 8 degrees
<h3>How to calculate the angle TOU ?</h3>
∠SOR = ∠TOU (Vertically opposite angles are equal).
Therefore:
13 x = 15x - 8
Subtracting 13x from both sides
13x - 13x = 15x - 8 - 13x
0 = 15x - 13x - 8
2x - 8 = 0
Adding 8 to both sides:
2x - 8 + 8 = 0 + 8
2x = 8
2x/2 = 8/2
x = 4
∠SOR = 13x
= 13(4)
= 52°
∠TOU = 15x - 8
= 15(4) - 8
= 60 - 8
= 52°
Let a = mArc R V = mArc V U
Therefore:
mArc R V + mArc V U + ∠TOU = 180 (sum of angles on a straight line)
Substituting:
a + a + 52 = 180
2a = 180-52
2a = 128
a = 128/2
a= 64°
mArc R V = mArc V U = 64°
In circle O, RT and SU are diameters. mArc R V = mArc V U = 64°. Thus, option C is correct.
Learn more about angles here:
brainly.com/question/2882938
#SPJ1
Answer:

Step-by-step explanation:
Amount of kool - aid that the pitcher can hold =
gallons
There are 6 smaller containers in which this kool - aid is to be adjusted.
Also, the volume of the smaller containers is equal to each other i.e. the containers are identical to each other in terms of volume.
To find:
The amount of kool - aid that each container can hold?
Solution:
Volume of all the smaller containers combined = Volume of the kool - aid available
Let the volume of one smaller container = 


of kool - aid is the amount that each smaller can hold.
Answer:

General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
<u>Trigonometry</u>
[Right Triangles Only] SOHCAHTOA
[Right Triangles Only] sinθ = opposite over hypotenuse
Step-by-step explanation:
<u>Step 1: Identify Variables</u>
Angle θ = 23°
Opposite Leg = <em>x</em>
Hypotenuse = 21
<u>Step 2: Solve for </u><em><u>x</u></em>
- Substitute in variables [sine]:

- [Multiplication Property of Equality] Isolate <em>x</em>:

- Rewrite:

- Evaluate:

- Round:
